Question

我的api得到像这样的json数据

 Office "دكتور نيوترشن"
officename  "11111111"
 address_user   "سيتي مول"
profile_photo   "profile_photo.png"
cover_photo "cover_photo.jpg"
agentarea   "القطيف"
offertext   "قريبا سوف توضح المصومات"
websiteurl  "albatool-hdo"

在xamarin android我正在创建这个类

    public class Galeri
   {
    public Galeri()
    {
    }


    public string Office { get; set; }
    public string officename { get; set; }
    public string address_user { get; set; }
    public string profile_photo { get; set; }
    public string cover_photo { get; set; }
    public string agentarea { get; set; }
    public string offertext { get; set; }
    public string websiteurl { get; set; }
    public string membertype { get; set; }

}

我也正在使用此代码反序列化json

        RunOnUiThread(() =>
        {
            itemGaleri = JsonConvert.DeserializeObject<List<Galeri>>(e.Result);
            CustomListAdapter adapter = new CustomListAdapter(this, itemGaleri);
            DaftarGaleri.Adapter = adapter;
            progress.Visibility = ViewStates.Gone;
            DaftarGaleri.ItemClick += DaftarGaleri_ItemClick;

        }
        );

但是我收到了错误

    Cannot deserialize the current JSON object (e.g. {"name":"value"})        into type '' because the type requires a JSON array (e.g. [1,2,3]) to  deserialize correctly.

Answer 1

下次当您必须处理JSON并且想要快速生成C＃模型时，请使用https://app.quicktype.io之类的服务。现在只需为您的属性提供逻辑名称，例如Galeri而不是Welcome。

// To parse this JSON data, add NuGet 'Newtonsoft.Json' then do:
//
//    using QuickType;
//
//    var data = Welcome.FromJson(jsonString);

namespace QuickType
{
    using System;
    using System.Net;
    using System.Collections.Generic;

    using Newtonsoft.Json;

    public partial class Welcome
    {
        [JsonProperty("Office")]
        public string Office { get; set; }

        [JsonProperty("officename")]
        public string Officename { get; set; }

        [JsonProperty("address_user")]
        public string AddressUser { get; set; }

        [JsonProperty("profile_photo")]
        public string ProfilePhoto { get; set; }

        [JsonProperty("cover_photo")]
        public string CoverPhoto { get; set; }

        [JsonProperty("agentarea")]
        public string Agentarea { get; set; }

        [JsonProperty("offertext")]
        public string Offertext { get; set; }

        [JsonProperty("websiteurl")]
        public string Websiteurl { get; set; }

        [JsonProperty("membertype")]
        public string Membertype { get; set; }
    }

    public partial class Welcome
    {
        public static Welcome[] FromJson(string json) => JsonConvert.DeserializeObject<Welcome[]>(json, Converter.Settings);
    }

    public static class Serialize
    {
        public static string ToJson(this Welcome[] self) => JsonConvert.SerializeObject(self, Converter.Settings);
    }

    public class Converter
    {
        public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
        {
            MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
            DateParseHandling = DateParseHandling.None,
        };
    }
}

无法将当前JSON对象（例如{＆＃34; name＆＃34;：＆＃34; value＆＃34;}）反序列化为类型，因为该类型需要JSON数组

1 个答案: