Question

我将一个声明文件添加到打包的typescript中。有一些这样的语法：

import * as Sequelize from 'sequelize'; // this @types/sequelize export a namespace
//...
interface Application{
    Sequelize: Sequelize; // <---error TS2709: Cannot use namespace 'Sequelize' as a type.
}

所以我写了一个这样的文件（index.d.ts）：

// 0 =  eldest = pre
//everytime i run this code i get names in pattern that makes no sense to me

public class cousin {

    public static void main(String[] args) 
    {
        String[] children = {"Arm", "Jo", "Ra", "Jas", "Pre", "She"};

        int[] sortAge =          {2, 4, 3, 5, 0, 1};

        int x = 0;
        int y = 1;


        while ( x < 6)
        {
            int ref = sortAge[x];   
            System.out.print(y+ "\t");
            System.out.println(children[ref]);
            x = x + 1;
            y = y + 1;      }

    }

}

如何解决这个问题？

Answer 1

您的import语句表示您要从sequelize模块导入所有内容，并将其放在名为Sequelize的名称空间中。

您需要引用以namespace.member方式导入的任何成员 - 在您的示例中Sequelize.Sequelize，尽管作为个人偏好，我会重命名命名空间以避免重复。

import * as Sequelize from 'sequelize'; 
//...

interface Application{
    Sequelize: Sequelize.Sequelize; 
}

如何将命名空间分配给typescript中的类的属性

1 个答案: