Question

我正在为学校做一个迷你项目。我试着调用我已定义的函数。它工作但事情是我在第40行调用函数，函数定义在第56行。为什么它工作？是因为整个编译器和解释器都不对吗？

我在脚本模式下使用PyCharm。

def game_intro():

print "------------------ First Hero ------------------"
global n1
n1 = raw_input("Please Type a Name for Your Hero: ")

while not valid_name(n1):
    print "------------------ First Hero ------------------"
    n1 = raw_input("Please Type a Name for Your Hero: ")

print "------------------ Second Hero ------------------"
global n2
n2 = raw_input("Please Type a Name for Your Hero: ")

while not valid_name(n2):
    print "------------------ Second Hero ------------------"
    n2 = raw_input("Please Type a Name for Your Hero: ")
while not no_repeat(n2):
    n2 = raw_input("Please Type a Name for Your Hero: ")





def valid_name(n):

if n == " ":   # TO AVOID THE PLAYER GIVING A NAME AS SPACE

    print "Your name can't be empty"
    return False

elif n == "":
    return False
return True




def no_repeat(m):  # TO MAKE SURE THE PLAYERS WON'T TAKE THE SAME NAME

if m == n1:

    print m + " Already Assigned, Please Type a Different Name."

    return False

return True

Answer 1

您似乎忘记了在函数中缩进代码。

您还应添加if __name__ == '__main__'行，以便您可以像脚本一样运行代码：

python test.py

请尝试以下代码：

test.py

def game_intro():

    print "------------------ First Hero ------------------"
    global n1
    n1 = raw_input("Please Type a Name for Your Hero: ")

    while not valid_name(n1):
        print "------------------ First Hero ------------------"
        n1 = raw_input("Please Type a Name for Your Hero: ")

    print "------------------ Second Hero ------------------"
    global n2
    n2 = raw_input("Please Type a Name for Your Hero: ")

    while not valid_name(n2):
        print "------------------ Second Hero ------------------"
        n2 = raw_input("Please Type a Name for Your Hero: ")
    while not no_repeat(n2):
        n2 = raw_input("Please Type a Name for Your Hero: ")


def valid_name(n):

    if n == " ":   # TO AVOID THE PLAYER GIVING A NAME AS SPACE

        print "Your name can't be empty"
        return False

    elif n == "":
        return False
    return True


def no_repeat(m):  # TO MAKE SURE THE PLAYERS WON'T TAKE THE SAME NAME

    if m == n1:

        print m + " Already Assigned, Please Type a Different Name."

        return False

    return True

if __name__ == '__main__':
    game_intro()

Answer 2

关于如何调用函数而不用担心顺序的简单答案是使用if __name__ ==“ __main__”，例如

def fun2():
   pass
def fun1():
   pass

if __name__ == "__main__"
    func1()
    func2()

如前所述。但是，如果我是您，我将使用类进行完全控制。我会做类似的事情：

import random
class Hero:
    def __init__(self):
        # Game Intro
        print('-'*18,'First Hero','-'*18)
        # First Hero
        while True:
            n1 = input('Type  Your Hero\'s name: ')
            # For beauty and rejecting Jim, jim
            self.n1 = n1.capitalize()
            if self.n1.split():
                break
            print('Invalid Hero\'s name\n')
        print('-'*18,'Second Hero','-'*18)
        # Second Hero
        while True:
            n2 = input('Type  Your Second Hero\'s name: ')
            self.n2 = n2.capitalize()

            if self.n2.split():
                if self.n1 == self.n2:
                    print('\nOh! We have a hero by name',self.n2)
                    self.n2 = print('Change Second Hero\'s name: ')
                else:
                    break
            print('Invalid Hero\'s name\n')

    # just a random silly game
    def chance_game(self):
        win = ['Awesome','Bravo','You Rock']
        los = ['Next time', 'Almost won','Never quit']

        p1 = random.randint(1,10)
        p2 = random.randint(1,10)

        if p1 > p2:
            print(random.choice(win),self.n1)
            print(random.choice(los),self.n2)
        else:
            print(random.choice(win),self.n2)
            print(random.choice(los),self.n1)

# Initiate your intro
game = Hero()

# Use the variable else where e.g. chance game
game.chance_game()

如果输入为空，则

stringValue.split（）返回False。原始条件不会包含双倍空格;）

如果我在我定义函数的行之前调用一行上的函数，为什么我的代码工作？

2 个答案: