Question

我有以下sql查询：

SELECT
    dbo.Stores.Store_Name,
    SUM(tziros_imeras) AS tziros_imeras,
    SUM(tziros_imeras_X_fpa) AS tziros_imeras_X_fpa,
    SUM(polithenta_karotsia) AS polithenta_karotsia,
    SUM(polithenta_kathismata) AS polithenta_kathismata,
    SUM(ask_for_furni) AS ask_for_furni,
    SUM(ask_for_karotsi) AS ask_for_karotsi,
    SUM(ask_for_kathisma) AS ask_for_kathisma,
    SUM(furni_reservation) AS furni_reservation,
    SUM(tziros_imeras) AS tziros_imeras
FROM
    dbo.Reports,
    dbo.Stores
WHERE
    dbo.Reports.Store_id = dbo.Stores.Store_id
GROUP BY 
    dbo.Stores.Store_Name
ORDER BY 
    dbo.Stores.Store_Name ASC

这个查询很完美，他做了我真正需要做的事情（我在循环中得到了理想的结果）。

我的问题是我需要在我的搜索结果中包含更多信息。我想要表格nomisma中的Nomismata列信息。

与此相关的表格如下：Stores＆amp; Nomismata并且它们具有以下结构：

Stores（Store_id，fpa_id，nomisma_id，Store_Name，Store_password）
Nomismata（nomisma_id，nomisma）

是否有任何方法可以在我的查询中正确包含nomisma信息？

Answer 1

首先，我建议在“FROM”子句中使用“JOIN”（INNER，LEFT，RIGHT ......）：

FROM
    dbo.Reports,
    dbo.Stores
WHERE
    dbo.Reports.Store_id = dbo.Stores.Store_id
GROUP BY 
    dbo.Stores.Store_Name
ORDER BY 
    dbo.Stores.Store_Name ASC

到

FROM
    dbo.Reports  
INNER JOIN 
    dbo.Stores ON dbo.Reports.Store_id = dbo.Stores.Store_id
GROUP BY 
    dbo.Stores.Store_Name
ORDER BY 
    dbo.Stores.Store_Name ASC

...现在，包括你的新表：

SELECT
    dbo.Stores.Store_Name, 
    Nomismata.nomisma,
    SUM(tziros_imeras) AS tziros_imeras,
    SUM(tziros_imeras_X_fpa) AS tziros_imeras_X_fpa,
    SUM(polithenta_karotsia) AS polithenta_karotsia,
    SUM(polithenta_kathismata) AS polithenta_kathismata,
    SUM(ask_for_furni) AS ask_for_furni,
    SUM(ask_for_karotsi) AS ask_for_karotsi,
    SUM(ask_for_kathisma) AS ask_for_kathisma,
    SUM(furni_reservation) AS furni_reservation,
    SUM(tziros_imeras) AS tziros_imeras
FROM    
    dbo.Reports  
INNER JOIN 
    dbo.Stores ON dbo.Reports.Store_id = dbo.Stores.Store_id
INNER JOIN 
    Nomismata ON dbo.Stores.nomisma_id = Nomismata.nomisma_id
GROUP BY 
    dbo.Stores.Store_Name, Nomismata.nomisma
ORDER BY 
    dbo.Stores.Store_Name ASC

享受！

Answer 2

您可以在Nomismata列上添加Stores表（带nomisma_id表）的联接。在nomisma和SELECT子句中添加GROUP BY列。由于加入列为nomisma_id，因此我假设nomisma是一个维度而不是要求和的数字列。

还添加了JOIN而不是您拥有的交叉联接。这将使查询更有效。

SELECT
dbo.Stores.Store_Name, dbo.Nomismata.nomisma,
SUM(tziros_imeras) AS tziros_imeras,
SUM(tziros_imeras_X_fpa) AS tziros_imeras_X_fpa,
SUM(polithenta_karotsia) AS polithenta_karotsia,
SUM(polithenta_kathismata) AS polithenta_kathismata,
SUM(ask_for_furni) AS ask_for_furni,
SUM(ask_for_karotsi) AS ask_for_karotsi,
SUM(ask_for_kathisma) AS ask_for_kathisma,
SUM(furni_reservation) AS furni_reservation,
SUM(tziros_imeras) AS tziros_imeras
FROM
dbo.Reports 
JOIN dbo.Stores ON dbo.Reports.Store_id = dbo.Stores.Store_id
JOIN dbo.Nomismata ON dbo.Nomismata.nomisma_id = dbo.Stores.nomisma_id
GROUP BY dbo.Stores.Store_Name, dbo.Nomismata.nomisma
ORDER BY dbo.Stores.Store_Name ASC;

Answer 3

将Nomismata加入现有查询

选择
    Stores.Store_Name，
    Nomismata.nomisma，
    SUM（tziros_imeras）AS tziros_imeras，
    SUM（tziros_imeras_X_fpa）AS tziros_imeras_X_fpa，
    SUM（polithenta_karotsia）AS polithenta_karotsia，
    SUM（polithenta_kathismata）AS polithenta_kathismata，
    SUM（ask_for_furni）AS ask_for_furni，
    SUM（ask_for_karotsi）AS ask_for_karotsi，
    SUM（ask_for_kathisma）AS ask_for_kathisma，
    SUM（furni_reservation）AS furni_reservation，
    SUM（tziros_imeras）AS tziros_imeras
来自dbo.Reports报告
INNER JOIN dbo.Stores Stores
ON Reports.Store_id = Stores.Store_id
加入dbo.Nomismata Nomismata
ON Nomismata.nomisma_id = Stores.nomisma_id
GROUP BY Stores.Store_Name，
    Nomismata.nomisma
ORDER BY Stores.Store_Name

具有多个SUM的SQL查询语法

3 个答案: