Question

我有模特：图书馆可以有很多书。

现在我有一个用于在特定库中的书籍上执行CRUD的URL：

router.register(r'books/(?P<library_id>[0-9]+)', BookViewSet, base_name='books')

和相应的观点：

class BookViewSet(viewsets.ModelViewSet):

    serializer_class = BookSerializer
    def get_queryset(self):

        genre_query = self.request.query_params.get('genre', None)
        status_query = self.request.query_params.get('status', None)
        author_query = self.request.query_params.get('author', None)

        books = Book.objects.filter(which_library=self.kwargs.get('library_id'))
        if genre_query:
            books = books.filter(genre=genre_query)
        if status_query:
            books = books.filter(status=status_query)
        if author_query:
            books = books.filter(author=author_query)
        return books

我最初没有使用ModelViewSet，而是使用了@api_view装饰器的功能，其中一个是跟随的（返回过去两周添加的书籍，我有一个单独的URL作为api / books // new_arrivals这个函数）：< / p>

@api_view(['GET'])
def new_arrivals(request, library_id):
    """
    List all new arrival books in a specific library
    """
    d=timezone.now()-timedelta(days=14)
    if request.method == 'GET':
        books = Book.objects.filter(which_library=library_id)
        books = books.filter(when_added__gte=d)
        serializer = BookSerializer(books, many=True)
        return Response(serializer.data)

使用ModelViewSets时，我该怎么办？我必须添加另一个URL，然后为new_arrivals编写另一个类或在现有的BookViewSet中编写一个函数吗？在这种情况下如何实现处理这两种GET方法？

Answer 1

您可以通过添加特殊方法public APIGatewayProxyResponse FunctionHandler(APIGatewayProxyRequest request, ILambdaContext context) { context.Logger.LogLine("Get Request\n"); var path = "none"; if (request.PathParameters != null && request.PathParameters.Any()) { path = request.PathParameters["input"]; } var response = new APIGatewayProxyResponse { StatusCode = (int)HttpStatusCode.OK, Body = "Hello World. Here are is your path param: " + path, Headers = new Dictionary<string, string> { { "Content-Type", "application/json" }, { "Access-Control-Allow-Origin", "*" } } }; return response; }和list_route来扩展传统的viewSet。使用此装饰器，您可以添加ViewSet生成的新URL。在这种情况下，list_route更合适：

detail_route

这将为viewSet添加额外的网址：from rest_framework.decorators import list_route class BookViewSet(viewsets.ModelViewSet): ... @list_route() def new_arrivals(self, request): books = self.get_queryset() d=timezone.now()-timedelta(days=14) books = books.filter(when_added__gte=d serializer = self.get_serializer(books, many=True) return Response(serializer.data)。

Answer 2

list_route和detail_route已贬值，并与装饰器动作合并。

https://www.django-rest-framework.org/community/3.8-announcement/#deprecations

Django使用不同的URL休息ModelViewSet多个GET请求

2 个答案: