Bash：你如何提取两个句子之间的所有行？

Question

我有一个这样的文件：

When, in the course of human events, 
it becomes necessary for one people to dissolve 
*** Start copy here ***
the political bonds which have connected them 
with another, and to assume among the powers of 
*** End copy here ***
the earth, the separate and equal station to 
which the laws of nature and of nature's God entitle them 

我想编写一行终端命令来提取*** Start copy here ***和*** End copy here ***之间的行，所以输出应为：

the political bonds which have connected them 
with another, and to assume among the powers of 

我该怎么做？我不想使用awk（我一直在玩sed，但无法正确使用）以及我发现的其他回复单词而不是句子，这让我感到困惑。

Answer 1

关注awk可能对您有帮助。

awk '/*** End copy here ***/{flag="";next}/*** Start copy here ***/{flag=1;next} flag'  Input_file

Answer 2

sed -e '1,/^\*\*\* Start copy here \*\*\*$/d' -e '/^\*\*\* End copy here \*\*\*$/,$d' tmp.txt