Question

我使用acm库创建了一个简单的程序，该库接受用户输入的字符串并将其打印出来。这是该计划：

import acm.program.*;

public class morse extends Program{
    public void run(){

        String[] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
        String[] morse = {".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};
        String word = readLine("Give the word(s) to transcribe: ").toUpperCase();
        println("Morse: ");
        int j = 0;
        for(int i = 0; i < word.length(); i++){
            int k = 0;
            boolean flag = true;
            if(Character.toString(word.charAt(j)).equals(" ")){
                println();
            }else {
                while(!Character.toString(word.charAt(j)).equals(alphabet[k])){
                    if(k < 25){
                        k += 1;
                    }else{
                        println("Letter was not found.");
                        flag = false;
                        break;
                    }
                }
                if(flag){
                    println(morse[k] + " ");
                }
            j += 1;
            }   
        }
    }
}

但是，每次字符串包含空格时，不会打印空格后的所有内容。我真的无法找到背后的原因。任何人都可以帮我，甚至指点我吗？感谢

（空格后的字母全部打印为空格）

Answer 1

我不知道为什么你在i循环中定义for但从不使用它。您的主要问题是，当您遇到空格时，您不会增加j。我认为你有两个选择：

j

println();

增加if
完全删除j，只需使用i以前使用j的地方（可能是更好的主意）

您的代码的一般建议：您正在执行太多奇怪的字符和字符串逻辑。你可以做到

放弃alphabet
从char获取String，与您目前的方式相同
从中减去'A'
使用生成的char作为索引来访问morse数组
删除k和整个while循环。

为什么没有印刷空间后的所有东西？

1 个答案: