你想要多少骰子点?
6
尝试1:2
尝试2:4
尝试3:5
尝试4:6
在4尝试你发现6点
所以这就是我想要的输出,但似乎无法找到。
public abstract class Bar
{
public int MemberA {get;set;}
public string MemberB {get;set;}
}
public interface IBar
{
public int MemberA {get;set;}
public string MemberB {get;set;}
}
这就是我所拥有的。我现在尝试了一个for循环,但它似乎不起作用。有人能帮助我吗?
答案 0 :(得分:1)
请下次正确格式化您的问题,这有助于我们为您提供帮助:)
你需要一个while循环来掷骰子。
int dots = s.nextInt();
boolean found = false;
Random rnd = new Random();
while(!found) {
int rolled= rnd.nextInt(6) + 1;
if(rolled == dots) // do your stuff
found = true;
}
希望它有所帮助。
答案 1 :(得分:1)
你可以通过这种方式达到你想要的目标:
Scanner scan = new Scanner (System.in);
int randomValue = 0; //this is the random value that'd be autogenerated in each loop
int counter = 1; //this represents the number of trials
System.out.println("how many dice dots do u want?");
int dotsWanted = scan.nextInt();
while(randomValue != dotsWanted){
randomValue = (int) (6 * Math.random()) + 1;
counter++;
}
System.out.printf("In %d trials, %d dots were found\n", counter, dotsWanted);
我希望这有帮助..快乐编码!