Question

如何将数据从被动表单推送到firestore？我现在创建了反应形式，我只需要将信息推送到集合中。表格中的文件提交。如何用Angular 5实现这一目标？我写了反应形式，最后一部分是将数据推送到firebase。

这是当前的代码：从'@ angular / core'导入{Component，OnInit，OnDestroy}; 从'angularfire2 / firestore'导入{AngularFirestore，AngularFirestoreCollection}; 从'angularfire2 / database'导入{AngularFireDatabase}; 从'angularfire2 / auth'导入{AngularFireAuth}; 从'rxjs / Observable'中导入{Observable};

    import { FirestoreService } from '../../../../providers/firestore.service';

    import { Subject } from 'rxjs/Subject';
    import 'rxjs/add/operator/switchMap';
    import 'rxjs/add/observable/combineLatest';
    import * as firebase from 'firebase/app';

    import { ActivatedRoute } from '@angular/router';

    import { FormGroup, FormControl, Validators } from '@angular/forms';

    export interface Item {
    productName: '';
    productTitle: '';
    productPrice: '';
    productDescription: '';
    }

    @Component({
    selector: 'app-form',
    templateUrl: './form.component.html',
    styleUrls: ['./form.component.scss']
    })
    export class FormComponent implements OnInit {

    productId: any;
    prodId: string;
    ref: AngularFirestoreCollection<Item>;
    items: Observable<Item[]>;

    // for the form
    Item: FormGroup;
    FormGroup = this.db.col$('items');
    // end for the form

    private routeSubscribed: any;


    constructor(
        private route: ActivatedRoute,
        public db: FirestoreService,
        private afs: AngularFirestore
    ) { }

    ngOnInit() {
        this.ref = this.afs.collection('items');
        this.items = this.ref.valueChanges();
        this.items = this.db.col$('items');
        this.items = this.db.colWithIds$('items');
        this.productId = this.db.doc$(`items/${this.prodId}`);


        /// here is the form for products
        const data: Item = new Item ({
        productName: new FormControl('', {
            validators: Validators.required
        }),
        productTitle: new FormControl('', {
            validators: Validators.required
        }),
        productPrice: new FormControl('', {
            validators: Validators.required
        }),
        productDescription: new FormControl('', {
            validators: Validators.required
        })
        }, { updateOn: 'submit' } );
        // end here is the form for products
        this.afs.doc(`items/tops`).set(data);
        this.db.set(`items/tops`, data);

        }
        }

Answer 1

这就是我接近它的方式： 我假设您已完成所有设置以使用angularfire2

创建服务（items.service.ts）并建立连接和请求：（使用界面定义Item或创建模型文件，我更喜欢模型文件）

itemsCollection: AngularFirestoreCollection<Item>;
items: Observable<Item>;
collectionPath: string = "YOUR_PATH";

constructor(private afs: AngularFirestore) {
    this.itemsCollection = this.afs.collection(this.collectionPath);
}

addItem(item: Item){
    this.itemsCollection.add(item);
}

使用items.component.ts文件生成表单并推送数据：

item: Item;
itemForm: FormGroup;

constructor(private itemsService: ItemsService) { }

ngOnInit(){
    this.initForm()
}

private initForm(){
    this.itemForm = new FormGroup({
        'name' : new FormControl('', Validators.required),
        'title': new FormControl('', Validators.required)
        ......
    });
}

onSubmit(){
   this.itemService.addItem(this.itemForm.value);
}

在你的html文件中：
```
<form [formGroup]="itemForm"
      (ngSubmit)="onSubmit()">
```
并在您的输入中分配formControlName 并添加一个类型为＆＃34的提交按钮;提交＆＃34;

我希望它有所帮助。这是我第一次使用它，所以我道歉现在以更好的方式格式化答案。

如何将数据从被动表单推送到firestore？

1 个答案: