Question

我已经把头发撕了2天试图解决这个问题，我想知道你们有没有人可以提供帮助？我试图将XML字符串发布到服务器，他们声明“所有XML请求应使用HTTP POST方法使用”xml“参数名称发送到我们的服务器”。我已经尝试了很多方法来做到这一点但没有快乐（如果我使用带有表单的javascript它工作正常，但这对项目来说不实用）。请有人指出我正确的方向吗？我将首先在下面发布我无法工作的PHP / CURL代码，然后是可以正常工作的Javascript代码。我想我只是想模仿PHP / CURL代码中的Javascript

PHP / CURL代码

$xml = '<?xml version="1.0" encoding="UTF-8"?>
<Request>
   <Head>
      <Username>username</Username>
      <Password>password</Password>
      <RequestType>GetCities</RequestType>
   </Head>
   <Body>
      <CountryCode>MX</CountryCode>
  </Body>
</Request>';

$url = "http://example.com";

$ch = curl_init($url);

curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded'));
curl_setopt($ch, CURLOPT_POSTFIELDS, "$xml");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
echo $output;

curl_close($ch);

Javacript Code（有效）

function submitForm() {
var reqXML = "<Request><Head><Username>username</Username> <Password>password</Password><RequestType>GetCities</RequestType></Head><Body><CountryCode>MX</CountryCode></Body></Request>";
document.getElementById("xml-request").value = reqXML;
var xmlhttp;
if (window.XMLHttpRequest) {
    xmlhttp = new XMLHttpRequest();
} else {
    xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
        document.getElementById("xml-response").value = xmlhttp.responseText;
    }
}
xmlhttp.open("POST", "http://example.com", true);
xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xmlhttp.send("xml=" + reqXML);
return false;

Answer 1

由于您希望通过“xml”参数发送XML内容，您可能需要这样做：

curl_setopt($ch, CURLOPT_POSTFIELDS, "xml=" . $xml);

编辑：这是我的工作代码：

<?php

$xml = '<?xml version="1.0" encoding="UTF-8"?><Request><Head><Username>username</Username> <Password>password</Password><RequestType>GetCities</RequestType></Head><Body><CountryCode>MX</CountryCode></Body></Request>';

$url = "https://postman-echo.com/post"; // URL to make some test
$ch = curl_init($url);

curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded'));
curl_setopt($ch, CURLOPT_POSTFIELDS, "xml=" . $xml);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

$data = curl_exec($ch);
echo '<pre>';
echo htmlentities($data);
echo '</pre>';

if(curl_errno($ch))
    print curl_error($ch);
else
    curl_close($ch);

?>

PHP和CURL POST XML

1 个答案: