具有非连续时间值的jpgraph甘特图

时间:2018-01-03 12:02:20

标签: php jpgraph

通过阅读我管理的文档确实绘制了这样的情节。 enter image description here

该图的数据如下所示。

$data = array(
    array(0,"  Label 1", "2001-01-26 04:00","2001-01-26 14:00"),
    array(1,"  Label 2", "2001-01-26 10:00","2001-01-26 18:00"),
    array(2,"  Label 3", "2001-01-26","2001-01-26 10:00"),
    array(3,"  Label 3", "2001-01-26 13:20","2001-01-26 16:00")
);


for($i=0; $i<count($data); ++$i) {
    $bar = new GanttBar($data[$i][0],$data[$i][1],$data[$i][2],$data[$i][3],"",10);
    if( count($data[$i])>4 )
        $bar->title->SetFont($data[$i][4],$data[$i][5],$data[$i][6]);

    $graph1->Add($bar);
}

$graph1->Stroke();

如何更改它以获得这样的情节。

enter image description here

1 个答案:

答案 0 :(得分:1)

我从未使用甘特,但通过查看我可以猜测的代码 我保存了以前的标签并查看它是否与下一个标签匹配,如果是,我使用之前的数字和标签值。

$data = array(
    array(0,"  Label 1", "2001-01-26 04:00","2001-01-26 14:00"),
    array(1,"  Label 2", "2001-01-26 10:00","2001-01-26 18:00"),
    array(2,"  Label 3", "2001-01-26","2001-01-26 10:00"),
    array(3,"  Label 3", "2001-01-26 13:20","2001-01-26 16:00")
);
$prev ="";

for($i=0; $i<count($data); ++$i) {
    If($prev == $data[$i][1]){
        // Grab previous number and label.
        $bar = new GanttBar($data[$i-1][0],$data[$i-1][1],$data[$i][2],$data[$i][3],"",10);
    }Else{
        $bar = new GanttBar($data[$i][0],$data[$i][1],$data[$i][2],$data[$i][3],"",10);
    }
    if( count($data[$i])>4 )
        $bar->title->SetFont($data[$i][4],$data[$i][5],$data[$i][6]);

    $graph1->Add($bar);
    $prev = $data[$i][1]; // Label
}

$graph1->Stroke();

试一试,看看它是否有效。