我想在使用此功能的linkdiv
点击上创建弹出式div(名为linkcontent
持有td
div):
function getLinks(lid) {
document.getElementById('linkdiv').style.display = "block";
document.getElementById('linkdiv').style.visibility = "visible";
document.getElementById('linkcontent').innerHTML = "<div align=center><img src='images/spacer.gif' border=0 height=280 width=10 alt=''><br><img src='images_v2/loading.gif' border=0 alt='Loading content'></div>";
var lurl = "viewlinksdiv.php?lid="+lid;
if(window.XMLHttpRequest) {
reql = new XMLHttpRequest;
} else if(window.ActiveXObject) {
reql = new ActiveXObject("Microsoft.XMLHTTP");
}
if(reql) {
reql.onreadystatechange = getLinkResp;
reql.open("GET",lurl,true);
reql.send(null);
} else {
alert("Your browser does not support XMLHttpRequest technology!");
doesNotSupport = false;
}
}
而td
是..
echo "
<tr>
<td width=240 height=20 align=\ "left\" valign=\ "top\" style=\ "cursor:hand;cursor:pointer;padding-top:".$pad. ";padding-bottom:5px\" onclick=\ "getLinks('".$mid. "');return:false;\"><b class='news_date'>".$mdate." ".$cname.$mpol.":</b>
<font class='news_title'>".$msectname."</font><br>
<font class='news_date'>".$moretext."</font>
</td>
</tr>\n";
&#13;
我要展示的div是
<div id="linkdiv">
<div id="linkdiv_body">
<div id="tapclose" align="right" onclick="closeLink()" alt="Close">X</div>
<div id="linkcontent" class="linkdiv_font"></div>
</div>
</div>
此功能正在使用a href
元素,如
<a class="jslink" href="javascript:getLinks('3975')">link</a>
但不适用于td
onclick
元素。
这很奇怪,因为它使用相同的功能。
任何人都知道为什么这不起作用?
感谢。
答案 0 :(得分:0)
由于某些语法错误而未调用Javascript函数,请使用下面的代码更新您的PHP代码。另一件事是在你的onclick事件中你有&#34; return:false&#34;它应该是&#34;返回false&#34;
function getLinks(lid) {
alert("called");
document.getElementById('linkdiv').style.display = "block";
document.getElementById('linkdiv').style.visibility = "visible";
document.getElementById('linkcontent').innerHTML = "<div align=center><img src='images/spacer.gif' border=0 height=280 width=10 alt=''><br><img src='images_v2/loading.gif' border=0 alt='Loading content'></div>";
var lurl = "viewlinksdiv.php?lid="+lid;
if(window.XMLHttpRequest) {
reql = new XMLHttpRequest;
} else if(window.ActiveXObject) {
reql = new ActiveXObject("Microsoft.XMLHTTP");
}
if(reql) {
reql.onreadystatechange = getLinkResp;
reql.open("GET",lurl,true);
reql.send(null);
} else {
alert("Your browser does not support XMLHttpRequest technology!");
doesNotSupport = false;
}
}
以及工作示例如下
<table>
<tr>
<td style="cursor:hand;cursor:pointer;padding-top:10;padding-bottom:5px" onclick="getLinks('9999');return false;" width="240" valign="top" height="20" align="left"><b class="news_date">1/1/2017 TestTestMPol:</b>
<font class="news_title">Test</font><br>
<font class="news_date">More</font>
</td>
</tr>
</table>
&#13;
private IDisposable planeSpottedSubscription;
jetfighter.PlaneSpotted.Where(x => string.Equals(x.Name, “Eurofighter”)).Subscribe(this.OnPlaneSpotted);
&#13;
你可以点击&#34; TestTestMPol&#34;你会看到一个警报。