Question

表：

Id Name Age Country
1  AAAA 12  AU
2  BBBB 13  CC

如何将结果作为KEYVALUE PAIR的TAB获取列名和相应的值？例如，对于id 1，结果应该类似于

[
  {Name:AAAA},
  {Age: 12},
  {Country: AU}
]

Answer 1

您可以使用UNPVIVOT和LISTAGG。

SELECT ID,   
    '['|| 
        LISTAGG ('{' || col || ':' || VALUE || '}', ',')
        WITHIN GROUP (ORDER BY ROWNUM)
    || ']'  key_value_pair
FROM (SELECT id,Name, TO_CHAR (age) age, Country FROM yourtable) 
UNPIVOT (VALUE FOR col IN (Name, Age, Country)) 
GROUP BY id;

<强>输出

| ID |                      KEY_VALUE_PAIR |
|----|-------------------------------------|
|  1 | [{NAME:AAAA},{AGE:12},{COUNTRY:AU}] |
|  2 | [{NAME:BBBB},{AGE:13},{COUNTRY:CC}] |

DEMO

你说你有TYPE KEYVALUEPAIR<VARCHAR,VARCHAR>。你可能想要使用这样的东西吗？

DECLARE
TYPE KEYVALUEPAIR
IS
  RECORD
  (
    KEY_   VARCHAR2(12),
    VALUE_ VARCHAR2(12) );
TYPE RECTYPE IS VARRAY(10) OF KEYVALUEPAIR;
RECID1 RECTYPE;
BEGIN
  SELECT col,
    VALUE BULK COLLECT
  INTO RECID1
  FROM
    (SELECT id, Name, TO_CHAR (age) age, Country FROM yourtable WHERE ID = 1
    ) UNPIVOT (VALUE FOR col IN (Name, Age, Country)) ;
END;
/

Answer 2

我不确定您的主要请求是使用VARARY集合还是以您提到的格式获取数据。

如果您需要使用VARRAY集合，请举例如下：

declare
    type t_1 is varray(10) of test_1%ROWTYPE;
    v_1 t_1:=t_1();
    j number;
begin
    v_1.extend(2);
    j := 1;
    for i in (select * from test_1)
    loop
        v_1(j).id       := i.id;
        v_1(j).name     := i.name;
        v_1(j).age      := i.age;
        v_1(j).country  := i.country;
        j := j + 1;
    end loop;

    for j in v_1.first .. v_1.last
    loop
        dbms_output.put_line ('v_1(' || j || ').id = ' || v_1(j).id);
        dbms_output.put_line ('v_1(' || j || ').name = ' || v_1(j).name);
        dbms_output.put_line ('v_1(' || j || ').age = ' || v_1(j).age);
        dbms_output.put_line ('v_1(' || j || ').country = ' || v_1(j).country);
        dbms_output.put_line ('---------------------------------');        
    end loop;
end;

列名和行值为oracle中的KEY VALUE PAIR类型

2 个答案: