Question

问题

你好，大家好。

我需要一些帮助来计算办理登机手续和退房员工白天和夜班工作之间的时间间隔。下面是表结构和查询的期望结果。有人可以帮忙吗？

签入和签出表格

EventTime   User    Status  Date
12/30/2017 6:38 User 1  Exit    12/30/2017
12/29/2017 18:18    User 1  Entry   12/29/2017
12/29/2017 17:14    User 4  Exit    12/29/2017
12/29/2017 9:14 User 4  Entry   12/29/2017
12/29/2017 18:23    User 2  Exit    12/29/2017
12/29/2017 6:33 User 2  Entry   12/29/2017
12/30/2017 6:38 User 3  Exit    12/30/2017
12/29/2017 18:18    User 3  Entry   12/29/2017

期望的结果：

User    Entry   Exit    Time duration   Date
User 1  12/29/2017 18:18    12/30/2017 6:38 12:19:56    12/29/2017
User 2  12/29/2017 6:33 12/29/2017 18:23    11:49:52    12/29/2017
User 3  12/29/2017 18:18    12/30/2017 6:38 12:19:56    12/29/2017
User 4  12/29/2017 9:14 12/29/2017 17:14    8:00:00 12/29/2017

Answer 1

条件聚合是一种方法

select t.[User], max(case when t.[status] = 'Entry' then t.EventTime end) [Entry],
                 max(case when t.[status] = 'Exit' then t.EventTime end) [Exist],
                 cast(cast(max(case when t.[status] = 'Exit' then t.EventTime end) as datetime) - 
                 cast(max(case when t.[status] = 'Entry' then t.EventTime end) as datetime) as time) [Time duration],
                 max(case when t.[status] = 'Entry' then t.[date] end) [Date]
from table t
group by t.[User]

注意：在上面用作varchar类型的日期时间，因为显然需要一些转换到datateime。所以，避免它。

结果：

User    Entry               Exist            Time duration      Date
User 1  12/29/2017 18:18    12/30/2017 6:38  12:20:00.0000000   12/29/2017
User 2  12/29/2017 6:33     12/29/2017 18:23 11:50:00.0000000   12/29/2017
User 3  12/29/2017 18:18    12/30/2017 6:38  12:20:00.0000000   12/29/2017
User 4  12/29/2017 9:14     12/29/2017 17:14 08:00:00.0000000   12/29/2017

Answer 2

以下是您的解决方案......

  SELECT EntryDtls.UserName,
          EntryDtls.EventTime        AS Entry,
          ExitDtls.EventTime         AS ExitDt,
          CAST(DATEDIFF(second, EntryDtls.EventTime, ExitDtls.EventTime) / 
          60 / 60 % 24  AS NVARCHAR(50))  +':'+
          CAST(DATEDIFF(second, EntryDtls.EventTime, ExitDtls.EventTime) / 
          60 % 60 AS NVARCHAR(50))  +':'+
          CAST(DATEDIFF(second, EntryDtls.EventTime, ExitDtls.EventTime) % 
          60 AS NVARCHAR(50))                                         AS 
          Time_duration,
          EntryDtls.Date
          FROM   (SELECT  *
          FROM  Trans_Tab
          WHERE Status = 'Entry')  AS EntryDtls
          JOIN   (SELECT  *
          FROM  Trans_Tab
          WHERE Status = 'Exit')  AS ExitDtls
          ON     (EntryDtls.UserName        =      ExitDtls.UserName)

计算日间员工和夜班员工的视图中的时间间隔

2 个答案: