我的输入总是被忽略

时间:2018-01-02 22:12:34

标签: java arrays input java.util.scanner line

所以,我试图找出为什么我的程序没有以正确的方式工作。我想在数组中保存东西,但第一个输入总是被忽略。例如,我问用户"你想输入更多的xy?"然后是一个是,我问有多少和最后一个添加的用户类型被忽略,第一个显示。如果它只有一个它甚至不显示。

这是我的代码

import java.util.*;
public class TriangleType {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int a , b ,c ,result , total,count;
        int x=9;
        String triangle = null;

     String[] output=new String[110];
        //storing types of traingles and their count for the statics display
        String[][] triangleTypes={{"gleichseitig","0"} ,{"gleichschenklig","0"},{"spitzwinklig","0"},{"rechtwinklig","0"},{"stumpwinkling","0"}};
        //2D array to store the sides of a traingle
        int[][] sides=new int[110][3];
        sides[0][0]=2;   sides[0][1]=2;      sides[0][2]=4;
        sides[1][0]=3;   sides[1][1]=4;      sides[1][2]=5;
        sides[2][0]=5;   sides[2][1]=5;      sides[2][2]=5;
        sides[3][0]=8;   sides[3][1]=6;      sides[3][2]=10;
        sides[4][0]=10;  sides[4][1]=10;     sides[4][2]=2;
        sides[5][0]=2;   sides[5][1]=4;      sides[5][2]=9;
        sides[6][0]=12;  sides[6][1]=36;     sides[6][2]=4;
        sides[7][0]=5;   sides[7][1]=6;      sides[7][2]=7;
        sides[8][0]=7;   sides[8][1]=9;      sides[8][2]=12;

        //User input
        System.out.println("Moechten Sie mehr Dreiecke hinzufuegen? (1/Ja/; 0/Nein/)");
        Scanner input = new Scanner(System.in);
        String s = input.nextLine();
        int equivalent=Integer.parseInt(s);
        if(equivalent==1){
            System.out.println("Wie viele Dreiecke moechten Sie hinzufuegen?");
            Scanner inputt = new Scanner(System.in);
            String ss = input.nextLine();
            total=Integer.parseInt(ss);
            for (int i=0; i<total; i++){
            System.out.println("Seite a von Dreieck   "+(8+i+1)+" eingeben:");
            Scanner input1 = new Scanner(System.in);
            String s1 = input1.nextLine();
            System.out.println("Seite b von Dreieck   "+(8+i+1)+" eingeben:");          Scanner input2 = new Scanner(System.in);
            String s2 = input2.nextLine();
            System.out.println("Seite c von Dreieck   "+(8+i+1)+" eingeben:");          Scanner input3 = new Scanner(System.in);
            String s3 = input3.nextLine();
            a=Integer.parseInt(s1);
            b=Integer.parseInt(s2);
            c=Integer.parseInt(s3);
             x=9+i;
            sides[9+i][0]=a;
            sides[9+i][1]=b;
            sides[9+i][2]=c;

        }}   

        for(int j=0; j<x; j++){
             triangle=evaluateTriangle(sides[j][0], sides[j][1], sides[j][2]);
             output[j]=triangle;

            System.out.println(sides[j][0]+" "+sides[j][1]+" "+sides[j][2] + " "+triangle);

        }
        for(int k=0; k<output.length; k++)
        {
            //check if returned triangle matches with one of defined types in triangleType array  
            for(int l=0; l<triangleTypes.length; l++ ){
                if(output[k]==triangleTypes[l][0])
                {  //if yes then update second member indicating no of occurences of that particular traingle
                 count=(Integer.parseInt(triangleTypes[l][1]));
                 count=count+1;
                 triangleTypes[l][1]=Integer.toString(count);
                }
            }


        }

        //show statistics
        System.out.println("======STATISTIK=======");
        System.out.println("Dreieckstyp  Anzahl");
        for(int m=0; m<triangleTypes.length; m++)
        {
        System.out.println(triangleTypes[m][0]+"  "+triangleTypes[m][1]);   
        }





    }
    //function to evaluate the type of triangle
    public static String evaluateTriangle(int side1 , int side2 , int side3){
        int a,b,c;
        a=side1;
        b=side2;
        c=side3;
        if(a <= 0 || b <= 0 || c <= 0)
        {return "kein gültiges Dreieck";}
        else if(a == b && b == c)
        {return "gleichseitiges Dreieck";}
        else if((a*a)+(b*b)==(c*c))
        {return "rechtwinkliges Dreieck";}
        else if((a*a)+(b*b)>(c*c))
        { return "spitzwinkliges Dreieck";}
        else if((a*a)+(b*b)<(c*c))
        { return "stumpwinklinges Dreieck";}
        else if (a == b || b == c || c == a)
        {return "gleichschenkliges Dreieck";}
        else return "undefiniert";


    }

}

对于长代码很抱歉,但我在这里绝望(也是java的新手)。 提前谢谢!

3 个答案:

答案 0 :(得分:1)

System.out.println("Wie viele Dreiecke moechten Sie hinzufuegen?");
Scanner inputt = new Scanner(System.in);
String ss = input.nextLine();

不应该是最后一个input.nextLine()是inputt.nextLine()?

如果要删除理解问题所需的所有行,将更容易调试。

答案 1 :(得分:1)

代码中用于打印结果的for循环不够高,将for循环更改为&lt; = x:

for(int j=0; j<=x; j++){
             triangle=evaluateTriangle(sides[j][0], sides[j][1], sides[j][2]);
             output[j]=triangle;

            System.out.println(sides[j][0]+" "+sides[j][1]+" "+sides[j][2] + " "+triangle);

        }

答案 2 :(得分:0)

更改行:

        for(int j=0; j<x; j++)

你的for循环没有到达最后一个元素,因为你需要在一个数组中找到11个元素,但你只索引它们中的十个,放:

        for(int j=0; j<=x; j++)
以这种方式到达

        sides[10][0]
        sides[10][1]
        sides[10][2]

包含未显示的数据