$this->db->where('scheme_id', 1);
$query = $this->db->get('scheme_installment');
$input = array();
// Flag to check if the amount is available to add in customer installment table
$hasMoreInstallments = TRUE;
foreach($query->result_array() as $item) {
$input['scheme_installment_id'] = $item['scheme_installment_id'];
$input['customer_id'] = $insert_id;
$input['created_date'] = date('Y-m-d H:i:s');
$input['last_modified_date'] = date('Y-m-d H:i:s');
$data['down_payment'] -= $item['installment_price'];
if( $hasMoreInstallments && $data['down_payment'] >= 0) {
$input['paid_date'] = date('Y-m-d H:i:s');
$input['comment'] = $hasMoreInstallments.' : '.$data['down_payment'];
if($data['down_payment'] >= $item['installment_price'] ) {
$input['amount'] = $item['installment_price'];
$input['status'] = 'Paid';
} else {
$input['amount'] = $data['down_payment'];
$hasMoreInstallments = FALSE;
}
}
$query = $this->db->insert('customer_installments', $input);
}
return $query;
基于hasMoreInstallments(True / False)我想插入数据。这里我无法停止插入,因为它没有将hasMoreInstallments的值修改为FALSE。每次循环运行时,它都将hasMoreInstallments视为TRUE,尽管记录也会打印在else块上。
答案 0 :(得分:0)
我认为在将变量减去之前没有将变量设置为值存在问题。
从我看到的变量$data['down_payment']
永远不会设置为例如0
,如下所示:
$data['down_payment'] = 0;
// now we can subtract from it
$data['down_payment'] -= 5;
但是,如果我们不为变量赋值并尝试从中减去值,则会有未定义的值可能会破坏您的脚本。
答案 1 :(得分:0)
它总是插入因为
$query = $this->db->insert('customer_installments', $input);
在if
条件
if($hasMoreInstallments && $data['down_payment'] >= 0)`{
...
}
//your insert is here