Question

database name is test1 and collection name is feedbacks 
this is app.js

我无法在我的html表单字段中获取mongodb数据正在插入数据，但我希望在我的表单中获取初始值帮助我解决这个问题。因为我是新手，我希望有一个简单明确的溶液

var express = require('express');
var path = require('path');
var bodyParser = require('body-parser');
var mongodb = require('mongodb');

var dbConn = mongodb.MongoClient.connect('mongodb://localhost:27017/test1');

var app = express();

app.use(bodyParser.urlencoded({ extended: false }));
app.use(express.static(path.resolve(__dirname, 'public')));

app.get('/retrieve', function(req, res){
    post.find({}, function(err, feedbacks){
        if(err) res.json(err);
        else    res.render('retrieve', {posts: feedbacks});
    });
});
app.post('/post-feedback', function (req, res) {
    dbConn.then(function(db) {
        delete req.body._id; // for safety reasons
        var dd = db.db("test1");

        dd.collection('feedbacks').insertOne(req.body);
    });    
    res.send('Data received:\n' + JSON.stringify(req.body));
});


app.get('/view-feedbacks',  function(req, res) {
    dbConn.then(function(db) {
        var dd=db.db("test1");
        dd.collection('feedbacks').find({"Name":"shubham"}).toArray().then(function(feedbacks) {
            res.status(200).json(feedbacks);
        });
    });
});
app.get('/view-sahil',  function(req, res) {
    dbConn.then(function(db) {
        var dd=db.db("test1");
        dd.collection('feedbacks').insertOne({"name":"sahil","E-mail":"sahil@vibhuti.guru","comment":"jhdsfji"},function(feedbacks) {
            res.status(200).json("Data inserted");
            });
        });
    });
 app.listen(process.env.PORT || 3000, process.env.IP || '0.0.0.0' );

这是我的index.html

<!doctype html>
<html lang="en">
<head>
    <script src="..app.js"></script>
    <meta charset="UTF-8">
    <title>mongodb</title>
</head>
<body>
    <h1>Please fill data in the form below:</h1>
    <form method="POST" action="/">
        <label>Name:<input type="text" name="" value= feedbacks.name required></label>
        <br>
        <label>Email:<input type="text" name="Email" value="" required></label>
        <br>
        <label>Comment:<br><textarea name="comment"></textarea></label>
        <br>
        <input type="submit" value="Submit">
    </form>


    <a href="/view-feedbacks">View Records</a>
    <a href="/view-sahil">insert dummy record </a>
</body>

</html>

Answer 1

你可以像angular_s这样调用API

var testApp = angular.module('testApp', []);

testApp.controller('testController' , function ($scope, $http) {

    $scope.getRequest = function () {
        console.log("I've been pressed!");  
        $http.get("http://localhost/view-feedbacks")
            .then(function successCallback(response){
                $scope.response = response;
                // Print this value in html 
            }, function errorCallback(response){
                console.log("Unable to perform get request");
            });
    };

});

使用jQuery，你可以这样做

 $.ajax({  
       type: "GET",  
       url: "http://localhost/view-feedbacks",  
       dataType: "json",  
       success: function(resp){  

         console.log("resp", resp);  
       },  
       error: function(e){  
         alert('error', e);  
       }  
     });

如何从mongodb到html表单字段中获取数据？

1 个答案: