Question

仅打印所有四个给定输入文件中存在的行。从下面显示的输入文件中只有/ dev / dev_sg2和/ dev / dev_sg3存在于所有输入文件中

$ cat file1
/dev/dev_sg1
/dev/dev_sg2
/dev/dev_sg3
/dev/dev_sg4

$ cat file2
/dev/dev_sg8
/dev/dev_sg2
/dev/dev_sg3
/dev/dev_sg6

$ cat file3
/dev/dev_sg5
/dev/dev_sg2
/dev/dev_sg3
/dev/dev_sg6

$ cat file4
/dev/dev_sg2
/dev/dev_sg3
/dev/dev_sg1
/dev/dev_sg4

尝试过的工具： -

cat file* | sort |uniq -c

      1 /dev/dev_sg1
      4 /dev/dev_sg2
      4 /dev/dev_sg3
      1 /dev/dev_sg4
      1 /dev/dev_sg5
      2 /dev/dev_sg6
      1 /dev/dev_sg8

Answer 1

使用 comm 管道：

comm -12 <(sort file1) <(sort file2) | comm -12 - <(sort file3) | comm -12 - <(sort file4)

-12 - 禁止两个输入文件唯一的行，仅打印公共行

输出：

/dev/dev_sg2
/dev/dev_sg3

Answer 2

关注awk代码可能对您有帮助。

awk 'FNR==NR{a[$0];next} ($0 in a){++c[$0]} END{for(i in c){if(c[i]==3){print i,c[i]+1}}}' Input_file1 Input_file2 Input_file3 Input_file4

输出如下。

/dev/dev_sg2 4
/dev/dev_sg3 4

编辑： 如果您不想计算行数，只想打印所有4个Input_files中的行，则按照会做的伎俩：

awk 'FNR==NR{a[$0];next} ($0 in a){++c[$0]} END{for(i in c){if(c[i]==3){print i}}}'  Input_file1 Input_file2 Input_file3 Input_file4

EDIT2： 现在也为代码添加说明。

awk '
FNR==NR{ ##FNR==NR condition will be TRUE when very first Input_file here Input_file1 is being read.
 a[$0];  ##creating an array named a whose index is current line $0.
 next    ##next is awk out of the box keyword which will avoid the cursor to go forward and will skip all next statements.
}
($0 in a){ ##These statements will be executed when awk complete reading the first Input_file named Input_file1 name here. Checking here is $0 is in array a.
 ++c[$0]   ##If above condition is TRUE then make an increment in array named c value whose index is current line.
}
END{       ##Starting END block of awk code here.
for(i in c){##Initiating a for loop here by which we will iterate in array c.
 if(c[i]==3){ ##checking condition here if array c value is equal to 3, which means it appeared in all 4 Input_file(s).
   print i    ##if, yes then printing the value of i which is actually having the line which is appearing in all 4 Input_file(s).
}
}}
' Input_file1 Input_file2 Input_file3 Input_file4 ##Mentioning all the 4 Input_file(s) here.

Answer 3

如果您事先知道不会有超过4个输入文件，您只需在现有解决方案的末尾添加grep，如下所示：

cat file* | sort |uniq -c | egrep '^4'

这将仅显示在行首处有最多（4）个计数的行。

如果您需要它来处理任意数量的文件，则需要更好的解决方案。

Answer 4

如果订单不需要维护

$ j() { join <(sort $1) <(sort $2); }; j <(j file1 file2) <(j file3 file4)

/dev/dev_sg2
/dev/dev_sg3

仅打印所有输入文件中存在的行

4 个答案: