Django:如何创建一个在用户点击时更改的动态表单?

时间:2018-01-01 20:36:29

标签: javascript python html django

我正在制作一个锻炼日历网站,用户可以在其中添加不同数量的电梯,套装和代表等的锻炼。因此,我需要一个在用户点击按钮时添加字段的表单。我已经制作了一个模板和一些javascript来描述我想要实现的目标:

URL:

url(r'^add/(?P<year>[0-9]+)/(?P<month>[0-9]+)/(?P<day>[0-9]+)/$', views.add_workout, name = 'add_workout')

模板:

{% block hidden %}
{% include "workoutcal/liftrow.html" %} {# To be used by Javascript #}
{% include "workoutcal/cardiorow.html" %}
{% endblock %}

<form action="{% url 'add_workout' date.year date.month date.day %}" method="post">

    <div class="row">
        <div class="col-xs-2">
            <p id="date">{{ date.year }}-{{ date.month }}-{{ date.day }}</p>
            <input type="hidden" name="date" value="{{ date }}">
        </div>
    </div>

    <h2 class="col-xs-12">Lifts</h2>
    <div id="liftrows">
        {% for i in range %}
          {% include "workoutcal/liftrow.html" %}
        {% endblock %}
    </div>

    <div class="row">
        <div class="col-xs-0"></div>
        <label class="col-xs-2"><button type="button" id="addliftbutton">One more lift</button></label>
    </div>



    <h2 class="col-xs-12">Cardio</h2>

    <div id="cardiorows">
        {% include "workoutcal/cardiorow.html" %}
    </div>

    <div class="row">
        <label class="col-xs-2"><button type="button" id="addcardiobutton">One more cardio</button></label>
    </div>
    <div class="row">
        <div class="col-xs-10"></div>
        <label class="col-xs-2"><input type="submit" id="submitbutton" value="Save Workout"></label>
    </div>
</form>

的javascript:

//Adding onclick to buttons
document.getElementById('addliftbutton').onclick = addLiftRow;
document.getElementById('addcardiobutton').onclick = addCardioRow;

for (var i=0; i<setsBoxes.length; i++){
    setsBox = setsBoxes[i];
    setsBox.onchange = insertRepFields;
}

function addLiftRow(){
    var liftRowElements = document.getElementById('liftrows');

    var hidden_liftrow = document.getElementById('hidden').getElementsByClassName('lift')[0];
    var new_liftrow = hidden_liftrow.cloneNode(true);

    liftRowElements.appendChild(new_liftrow);
}

function addCardioRow(){
    var cardiorows = document.getElementById('cardiorows');

    var hidden_cardiorow = document.getElementById('hidden').getElementsByClassName('cardio')[0];
    var new_cardiorow = hidden_cardiorow.cloneNode(true);

    cardiorows.appendChild(new_cardiorow);
}

function insertRepFields(){} // big function that inserts as many input fields as the number inside the box whose event called the function.

2个问题: 1.在Django中有更好的方法吗? 2.如果这是最好的方法,我如何将我的大型表格的数据发送回django?由于我不确切知道会有多少字段,因此我不知道如何创建一个接受不同字段和字段内字段的表单。

以下是填写表单的外观:

enter image description here

1 个答案:

答案 0 :(得分:1)

实现这一目标的最佳方法是插入具有相同名称的输入,然后在Django中将所有这些输入作为列表获取:

def view(request):
    inputs = request.POST.getlist('your_input_name')
    for i in inputs:
        Model.objects.create() # Save your model