我从JSON中提取联系人,数据中的联系人可能包含电子邮件和电话号码。
如果他们这样做,则以下查询完美运行:
var results = from d in json.Data
from c in d.Contacts
from e in c.Emails
from p in c.Phones
select new IoModel {Email = e.EmailValue, Id = d.Id, FullName = string.IsNullOrEmpty(c.Name) ? c.Name : d.DisplayName, Phone = p.PhoneNumber, DOB = d.CustomDOB};
如果数据没有电子邮件或电话,那么它运行时没有错误,但它不会返回联系人姓名。
有没有办法在不使用if和and来保持代码更短更清洁的情况下执行此操作?
以下是缺少电子邮件的JSON示例:
{
"data": [
{
"addresses": [],
"contacts": [
{
"created_by": "user_ltUL3eXGPRWb5ghDeGTfOe9qjW0LeE2e4ouopLcSSWj",
"date_created": "2017-12-28T17:13:00.392000+00:00",
"date_updated": "2017-12-28T17:13:58.453000+00:00",
"emails": [],
"id": "cont_6hxxhz51ctlTnHfo8gA8cce0rthS1dJy1kguKAj148s",
"integration_links": [
{
"name": "LinkedIn Search",
"url": "https://www.linkedin.com/search/results/index/?keywords=John%20Doe"
}
],
"lead_id": "lead_3UzfxCgQHmw4BlGwElitHhlP6E7q9Tg3sdSkTl1CIXp",
"name": "John Doe",
"organization_id": "orga_PvgGx1opSZDsCHl73P8OoSFZUlJ3qsNGI2kwgoObM17",
"phones": [
{
"phone": "+15555555555",
"phone_formatted": "+1 555-555-5555",
"type": "mobile"
}
],
"title": "Main Service",
"updated_by": "user_ltUL3eXXPRWb5shDeGTfOe9qjP0LeE2e4ouopLcSSWj",
"urls": []
}
],
"created_by": "user_ltUL3eXXPRWb5shDeGTfOe9qjW0LeE2e4ouopLcSSWP",
"created_by_name": "John",
"custom": {
"Date Of Birth": "1901-08-01",
"Department": "Main Service",
"Initial Service": "Main Service"
},
"custom.lcf_ufMH5ZhlR99zcdvJxKMxdgxcIbV4wtgTb3EdWDEkL8g": "1971-08-17",
"date_created": "2017-12-28T17:13:00.388000+00:00",
"date_updated": "2017-12-29T21:41:53.840000+00:00",
"description": "",
"display_name": "John Doe",
"html_url": "https://app.close.io/lead/lead_3UzfxCgQHmw4BlGwElitHhlP6E7q9Tg3sdSkTl1CIXp/",
"id": "lead_3UzfxCgQHmw4BlGwElitHhlP5E7q9Tg3sdSkTl1CIXp",
"integration_links": [
{
"name": "Google Search",
"url": "http://google.com/search?q=John%20Doe"
}
],
"name": "",
"opportunities": [],
"organization_id": "orga_AvcGx4opSZDsCHl73H8OogDDUlJ3qsNGI2kwgoObA17",
"status_id": "stat_LpJu8FO72WgIob4qDDVnS4GEieoU41zmQ8xBquTvusm",
"status_label": "Established Patient",
"tasks": [],
"updated_by": "user_0JFRnl8QRvRhMhAlLz4JJxgmrzPeLs3xboxYyj5Pm80",
"updated_by_name": "BT",
"url": null
}
],
"has_more": false,
"total_results": 1
}
答案 0 :(得分:2)
由于我不知道你要将你的JSON反序列化,我只能在这里猜测一个解决方案,但我想如果你在DefaultIfEmpty()
和{{1}上使用Emails
收集然后在Phones
和EmailValue
上使用空条件运算符,你应该得到你想要的结果:
PhoneNumber
答案 1 :(得分:2)
让我解释一下你遇到的问题。想象一下以下两个列表:
<强>问题强>
var ids = new List<int> { 1, 2, 3, 4 };
var names = new List<string>();
让我们编写一个Linq查询来获取所有id以及名称:
var idsAndNames = from id in ids
from name in names
select new { Id = id, Name = name };
以上查询将不返回任何结果。为什么?如果您使用foreach
而不是Linq,则更为明显。 foreach
版本大致如下所示:
foreach (var id in ids)
{
foreach (var name in names)
{
//select new { Id = id, Name = name };
}
}
很清楚也很明显为什么在上面的foreach
版本中不会返回任何结果(内部循环中的代码将不会被执行,因为names
列表为空)。
<强>修正强>
我们需要告诉我们的查询:如果names
集合中没有项目,我们将接受默认。我们可以使用DefaultIfEmpty
方法做到这一点。
var idsAndNames = from id in ids
from name in names.DefaultIfEmpty()
select new { Id = id, Name = name };
以上将返回4个结果。这有点像执行以下操作:
foreach (var id in ids)
{
if (names.Any())
{
//select new { Id = id, Name = name };
}
else
{
//select new { Id = id, Name = "" }; // <-- Notice empty string
}
}
回答您的问题
@BrianRogers已经回答了你的问题,但我详细说明了问题所在。