如何根据下拉列表将数据插入到不同的表中？

Question

我创建了一个可以接受两种类型用户的表单。 select标签中提供了不同的用户类型。我需要根据用户的选择将数据插入两个单独的表中。使用我当前的代码，我无法将数据插入任何一个表。大多数表单输入在两个表中都很常见。我还需要所有输入字段中的'required'属性。

这是表格的图像：

这是HTML：

<form action="login.php" method="post">

  <div class="field-wrap">
    <label>Name<span class="req">*</span></label>
    <input type="text" name="name" required autocomplete="off" />
  </div>                   
                    
  <div class="field-wrap">
    <label>Email Address<span class="req">*</span></label>
     <input type="email" name="email" required autocomplete="off" />
  </div>
                    
  <div class="field-wrap">
      <label>Phone Number<span class="req">*</span></label>
     <input type="tel" name="phone_no" required autocomplete="off" maxlength="10" />
  </div>

  <div class="field-wrap">
    <label>Set A Password<span class="req">*</span></label>
    <input type="password" name="password" required autocomplete="off" />
  </div>                   

<!--For selecting the type of user-->
                  
                    
  <div class="field-wrap combo">
                      
    <label>Account Type</label>
                              
    <select class="AccountType" id="account_type" name="account_type">
      <option value="AT" selected disabled hidden>Choose Your Account Type</option>
      <option value="User">User</option>
      <option value="Agent">Agent</option>               
    </select>                   
 
  </div>
                  
<!--These are the options available only for agents-->
  <div id="agent_options">
                        
    <div class="field-wrap">
      <label>Agency Name<span class="req">*</span></label>
      <input type="text" name="agency_name" <?php echo $required ?> autocomplete="off" />
    </div>        
                        
    <div class="field-wrap">
      <label>Street Name<span class="req">*</span></label>
      <input type="text" name="street_name" <?php echo $required ?> autocomplete="off" />
    </div>
                        
    <div class="field-wrap">
      <label>City<span class="req">*</span></label>
      <input type="text" name="city" <?php echo $required ?> autocomplete="off" />
     </div>
                        
    <div class="field-wrap">
      <label>State<span class="req">*</span></label>
      <input type="text" name="state" <?php echo $required ?> autocomplete="off" />
    </div>                     
                        
  </div>                   
                    
  <button type="submit" class="button button-block" name="register">CREATE ACCOUNT</button>

</form>

这是我用过的PHP代码。

 if(isset($_POST['register']))   
{

    if(isset($_POST['account_type']))
      {

        $account_type=$_POST['account_type']; 

        if($account_type=="Agent")
                    $required="required"; 
        else    
                    $required="";
        }


    if($account_type=="User")
    {
        $user_name=$_POST['name'];
        $email=$_POST['email'];
        $phone_no=$_POST['phone_no'];
        $password=$_POST['password'];

        $query="INSERT INTO user_details (user_name,email,phone_no,password) VALUES ('$user_name','$email','$phone_no','$password')";

        mysqli_query($connection,$query);   
    }
    else
    {
        $user_name=$_POST['name'];
        $email=$_POST['email'];
        $phone_no=$_POST['phone_no'];
        $password=$_POST['password'];
        $agency_name_name=$_POST['agency_name'];
        $street_name=$_POST['street_name'];
        $city=$_POST['city'];
        $state=$_POST['state'];

        $query="INSERT INTO agent_details (agent_name,email,phone_no,password,agency_name,street_name,city,state) VALUES ('$user_name','$email','$phone_no','$password','$agency_name','$street_name','$city','$state')";

        mysqli_query($connection,$query);

    }
}