Question

actor表架构

actor_id | first_name | last_name

我有查询

select a.actor_id, t.name,count(*) from actor a
LEFT JOIN 
(select fa.actor_id,fa.film_id,c.name  from film_actor fa
LEFT JOIN film_category fc ON fc.film_id=fa.film_id 
INNER JOIN category c ON c.category_id=fc.category_id
ORDER BY fa.film_id) t ON t.actor_id=a.actor_id
GROUP BY a.actor_id, t.name
ORDER BY a.actor_id

我收到了字段的结果

actor_id | name | count

我还希望在first_name表中包含last_name和actor，但我无法这样做，因为我只能选择group by子句中的那些列名。我希望{/ 1}} first_name在选择记录中，而不是将其添加到

组中

我希望我的结果为

last_name

Answer 1

您可以将列放在GROUP BY子句中：

SELECT a.first_name, a.last_name, a.actor_id, t.name,count(*) 
FROM actor a
LEFT JOIN (
    SELECT fa.actor_id,fa.film_id,c.name  
    FROM film_actor fa
    LEFT JOIN film_category fc 
    ON fc.film_id=fa.film_id 
    INNER JOIN category c 
    ON c.category_id=fc.category_id
    ORDER BY fa.film_id) t 
ON t.actor_id=a.actor_id
GROUP BY a.first_name, a.last_name, a.actor_id, t.name
ORDER BY a.actor_id

您可以使用concat()或format()或运算符||来连接字符串（请参阅String Functions and Operators），例如：

SELECT concat(a.first_name, ' ', a.last_name), a.actor_id, t.name,count(*) 
...

通过postgres选择备用字段名称组

1 个答案: