Question

我有一个非常讨厌的问题。我看到有些人有同样的问题，但我找不到合适的答案。

我正在Android Studio 3.0.1中开发一个非常简单的应用程序，它可以在ListView中显示图像和文本。

我想要在res / values / strings中显示我想要显示的所有字符串：

<string name="ka">ka</string>

我也有我的主要活动和其他一些活动。

我在AlphabetActivity中出现的问题，我试图获取字符串的id：

int asd = R.string.ka;

这只是一种简化，但这是不起作用的。我无法以某种方式达到ID，或者出现了问题，但我不知道该怎么做以及如何对它进行操作。

我收到以下错误消息：

android.content.res.Resources$NotFoundException: Drawable japanese.japanese:string/ka with resource ID #0x7f0b004a
              Caused by: android.content.res.Resources$NotFoundException: File ka from drawable resource ID #0x7f0b004a

并且该列表将继续使用＆＃34;作为android.something ...＆＃34;

如果有人知道导致这个问题的原因，我会很感激，这很烦人。

我还检查了R文件，一切似乎都在那里，所以我不明白为什么它找不到ID-s。

感谢您的回答！

public class AlphabetActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.alphabet_list);

    final ArrayList<AlphabetContainer> sets = new ArrayList<AlphabetContainer>();
    sets.add(new AlphabetContainer(R.string.a, R.string.i, R.string.u, R.string.e, R.string.o, R.drawable.a, R.drawable.i, R.drawable.u, R.drawable.e, R.drawable.o));

    AlphabetContainerAdapter adapter = new AlphabetContainerAdapter(this, sets);

    ListView listView = (ListView) findViewById(R.id.alphabetList);

    listView.setAdapter(adapter);

}

}

public class AlphabetContainerAdapter extends ArrayAdapter<AlphabetContainer>{

public AlphabetContainerAdapter(Context context, ArrayList<AlphabetContainer> alphabet){
    super(context, 0, alphabet);
}

@Override
public View getView(int position, View convertView, ViewGroup parent){
    View listItemView = convertView;
    if(listItemView == null){
        listItemView = LayoutInflater.from(getContext()).inflate(R.layout.alphabet_list_item, parent, false);
    }

    AlphabetContainer currentAlphabetContainer = getItem(position);

    TextView alphabetTextView = (TextView) listItemView.findViewById(R.id.text1);

    alphabetTextView.setText(String.valueOf(currentAlphabetContainer.getAlphabetId1()));

    ImageView alphabetImageView = (ImageView) listItemView.findViewById((R.id.image1));

    if(currentAlphabetContainer.hasImage1()){
        alphabetImageView.setImageResource(currentAlphabetContainer.***getAlphabetId1***());
        alphabetImageView.setVisibility(View.VISIBLE);
    }
    else{
        alphabetImageView.setVisibility(View.GONE);
    }

    return listItemView;
}

}

public class AlphabetContainer {
//string source ID for the letter
private int mAlphabetId1;
private int mAlphabetId2;
private int mAlphabetId3;
private int mAlphabetId4;
private int mAlphabetId5;

//image source ID for the letter
private int mImageId1 = NO_IMAGE_PROVIDED;
private int mImageId2 = NO_IMAGE_PROVIDED;
private int mImageId3 = NO_IMAGE_PROVIDED;
private int mImageId4 = NO_IMAGE_PROVIDED;
private int mImageId5 = NO_IMAGE_PROVIDED;

private static final int NO_IMAGE_PROVIDED = -1;

//constructor
public AlphabetContainer(int alphabetId1, int alphabetId2, int alphabetId3, int alphabetId4, int alphabetId5, int imageId1, int imageId2, int imageId3, int imageId4, int imageId5){
    mAlphabetId1 = alphabetId1;
    mAlphabetId2 = alphabetId2;
    mAlphabetId3 = alphabetId3;
    mAlphabetId4 = alphabetId4;
    mAlphabetId5 = alphabetId5;
    mImageId1 = imageId1;
    mImageId2 = imageId2;
    mImageId3 = imageId3;
    mImageId4 = imageId4;
    mImageId5 = imageId5;
}

public int getAlphabetId1(){return mAlphabetId1;}
public int getAlphabetId2(){return mAlphabetId2;}
public int getAlphabetId3(){return mAlphabetId3;}
public int getAlphabetId4(){return mAlphabetId4;}
public int getAlphabetId5(){return mAlphabetId5;}

public int getImageId1(){return mImageId1;}
public int getImageId2(){return mImageId2;}
public int getImageId3(){return mImageId3;}
public int getImageId4(){return mImageId4;}
public int getImageId5(){return mImageId5;}

public boolean hasImage1(){return mImageId1 != NO_IMAGE_PROVIDED;}
public boolean hasImage2(){return mImageId2 != NO_IMAGE_PROVIDED;}
public boolean hasImage3(){return mImageId3 != NO_IMAGE_PROVIDED;}
public boolean hasImage4(){return mImageId4 != NO_IMAGE_PROVIDED;}
public boolean hasImage5(){return mImageId5 != NO_IMAGE_PROVIDED;}

}

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    ////test
    int asd = R.string.bo;
    ////test

    TextView alphabetTextView = (TextView) findViewById(R.id.alphabetView);
    alphabetTextView.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v){
            setContentView(R.layout.activity_alphabet);
        }
    });

    TextView alphabetTextView2 = (TextView) findViewById(R.id.alphabetGameView);
    alphabetTextView2.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Intent alphabetIntent = new Intent(MainActivity.this, AlphabetActivity.class);

            startActivity((alphabetIntent));
        }
    });
}

}

我正处于学习过程的开始阶段，所以我的代码可能不那么漂亮，抱歉：）

Answer 1

这不是名称为“static navigationOptions = ({ navigation }) => { const { params = {} } = navigation.state; const title = `This is ${params.title}`; return { title }; };”的字符串资源的问题。在您的应用程序中的某个位置，您尝试使用导致问题的R.string.ka进行访问。

或

尝试使缓存无效并重试。

错误消息：android.content.res.Resources $ NotFoundException

1 个答案: