在INSERT（PHP）中将2个不同的查询合并为一个

Question

我有两张桌子，他们是

name
- fname
- sport_id (FK)

sports
- id (PK)
- football
- basketball

所以我为INSERT

做了这个

mysqli_query($mysqli, "INSERT INTO name(fname)
    VALUES('$fname')");
mysqli_query($mysqli, "INSERT INTO sprots(football, basketball)
    VALUES('$football','$basketball')");

是正确的吗？或者我应该将它们合并到一个查询中？关系和身份怎么样？

Answer 1

您需要首先将数据插入sports表，然后从sports表中获取最后插入的ID，然后插入名称表

获取最后插入的ID

mysqli_query($mysqli, "INSERT INTO sports(football, basketball) VALUES('$football','$basketball')");

$last_id = mysqli_insert_id($mysqli); 

mysqli_query($mysqli, "INSERT INTO name(fname,sport_id ) VALUES('$fname','$last_id')");

Answer 2

正如评论中所建议的那样：

// Insert into sports table
mysqli_query($mysqli, "INSERT INTO sports(football, basketball)
    VALUES('$football','$basketball')");

// Get last inserted id (in sports table)
$sport_id = mysqli_insert_id($mysqli);

// Insert it into name table
mysqli_query($mysqli, "INSERT INTO name(sport_id,fname)
VALUES('$sport_id','$fname')");