我无法弄清楚如何在服务数据条件下测试组件方法是否被触发......
服务看起来像:
@Injectable()
export class SomeService {
someData() {
return true;
}
}
排版:
export class SomeComponent {
constructor(private someService: SomeService) {
if (this.someService.someData()) {
this.someMethod();
} else {
console.log('keep kalm!');
}
}
someMethod() {
console.log('some method is fired!')
}
}
试验:
describe('SomeComponent', () => {
let component: SomeComponent;
let fixture: ComponentFixture<SomeComponent>;
let mockSomeService = {
someData: () => true
}
beforeEach(async(() => {
TestBed.configureTestingModule({
declarations: [SomeComponent],
providers: [
{
provide: SomeService, useValue: mockSomeService
}
]
})
.compileComponents();
}));
beforeEach(() => {
fixture = TestBed.createComponent(SomeComponent);
component = fixture.componentInstance;
fixture.detectChanges();
});
it('method should be called', () => {
spyOn(component, 'someMethod');
expect(component.someMethod).toHaveBeenCalled();
});
});
someMethod组件触发,但测试失败:
预期间谍someMethod被调用。
我该如何解决这个问题?
提前致谢!
答案 0 :(得分:2)
你必须在创建组件之前创建间谍,因为间谍不能过去看,因为你的方法只在构造函数中调用,所以它还没有在你创建间谍后调用。
您应该将初始化移至ngOnInit
方法或构造函数中调用的简单init()
方法,这样可以调用init
方法或ngOnInit
并检查someMethod
被称为。{/ p>
答案 1 :(得分:1)
someMethod
。所以在defining
之后,组件会调用间谍
it('method should be called', () => {
var spy = spyOn(component, "someMethod").and.callThrough();
expect(component).toBeDefined();
expect(spy);
expect(component.someMethod).toHaveBeenCalled();
});
答案 2 :(得分:1)
Oke它是固定的!感谢@Supamiu的回答
将来有人会需要它:
将初始化移动到ngOnInit中,删除fixture.detectChanges();来自beforeEach并在测试中执行它。所以:
小样:
constructor(private someService: SomeService) { }
ngOnInit() {
if (this.someService.someData()) {
this.someMethod();
} else {
console.log('keep kalm!');
}
}
试验:
beforeEach(() => {
fixture = TestBed.createComponent(SomeComponent);
component = fixture.componentInstance;
// fixture.detectChanges(); <<< Remove this
});
it('method should be called', () => {
spyOn(component, 'someMethod');
fixture.detectChanges(); // trigger ngOnInit here
expect(component.someMethod).toHaveBeenCalled();
});