Question

我有springboot应用程序，而不是部署到tomcat。我上课了：

public List<CaseListEntry> GetCaseListEntries()
    {
        var CaseGridTrs = CaseListGrid.FindElements(By.XPath(".//tr"));
        var entryList = CaseGridTrs.Select(x =>
        {
            var CaseEntryTds        = x.FindElements(By.XPath(".//td"));

            var ListNoElement       = GetElementOrNull(CaseEntryTds,0);
            var RegisterDateElement = GetElementOrNull(CaseEntryTds,1);
            var DocumentTypeElement = GetElementOrNull(CaseEntryTds,2);
            var RegisterNoElement   = GetElementOrNull(CaseEntryTds,3);


            var RegisterDate        = (RegisterDateElement != null)? RegisterDateElement.Text : "";
            var RegisterNo          = (RegisterNoElement != null)? RegisterNoElement.Text : "";
            var ListNo              = (ListNoElement != null) ? ListNoElement.FindElement(By.XPath(".//a")).Text : "";
            var DocumentType        = (DocumentTypeElement != null) ? DocumentTypeElement.Text : "";
            return new CaseListEntry
            {
                ListNo = ListNo ,
                RegDate = DateTime.ParseExact(RegisterDate, "dd.MM.yyyy",
                CultureInfo.InvariantCulture),
                DocumentType = DocumentType
            };
        }).ToList();
        return entryList;
    }

public IWebElement GetElementOrNull(IList<IWebElement> CaseEntryTds, int elementAtPosition, int maxSeconds = 1) {
    IWebElement element = null;
    IWait<IWebDriver> wait = new WebDriverWait(_driver, TimeSpan.FromSeconds(maxSeconds));
    wait.Until(d => {
        try {
            element = CaseEntryTds.ElementAt(elementAtPosition);
            return element.Displayed;
        } catch (WebDriverTimeoutException) {
            return false;
        } catch (NoSuchElementException) {
            return false;
        }
    });
  return element;

在application.properties中我有：

public class SpringBootApp    extends SpringBootServletInitializer  {
....
}

但是当应用程序部署到tomcat时，它不能与url一样： http://193.123.33.33:8080/ 通过网址http://193.123.33.33:8080/appname

购买

如何在tomcat中为root url映射设置springboot？谢谢！

Answer 1

配置文件中的

＆＃34; .yml＆＃34;文件需要声明

服务器：港口：8089 display-name：displayname

并且需要在tomcat属性中配置域名。但对于本地环境http：//将无法正常工作。

Answer 2

解决方法是在webapp tomcat文件夹中创建ROOT.war。

如何使用apache tomcat在spring boot中设置root url？

2 个答案: