Question

我使用的是jackson-databind：2.9.3和jackson-module-jaxb-annotations：2.9.3

我有以下格式的JSON。

{
    "response": {
        "data": {
            "entry": {
                "name": "xxxxxxxxxx"
            }
        }
    }
}

需要将此JSON响应反序列化为具有以下结构的类。

@XmlRootElement(name = "response")
public class Response {

    private List<Entry> entry;

    public Response() {
    }

    public Response(List<Entry> entry) {
        this.entry = entry;
    }

    @XmlElementWrapper(name = "data")
    @XmlElement(name = "entry")
    public List<Entry> getData() {
        return this.entry;
    }

    public void setData(List<Entry> entry) {
        this.entry = entry;
    }
}

public class Entry {

    private String name;

    public String getName() {
        return this.name;
    }

    public void setName(String name) {
        this.name = name;
    }
}

对于反序列化，我尝试了以下代码。但它不起作用。

    import com.fasterxml.jackson.databind.ObjectMapper;
    import com.fasterxml.jackson.databind.DeserializationFeature;
    import com.fasterxml.jackson.databind.MapperFeature;
    import com.fasterxml.jackson.databind.AnnotationIntrospector;
    import com.fasterxml.jackson.databind.type.TypeFactory;
    import com.fasterxml.jackson.databind.introspect.JacksonAnnotationIntrospector;
    import com.fasterxml.jackson.module.jaxb.JaxbAnnotationIntrospector

    ObjectMapper mapper = new ObjectMapper();
    mapper.configure(DeserializationFeature.UNWRAP_ROOT_VALUE, true);
    mapper.configure(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY, true);
    mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, true);


    mapper.configure(MapperFeature.USE_WRAPPER_NAME_AS_PROPERTY_NAME, true);
    mapper.configure(MapperFeature.USE_ANNOTATIONS, true);

    AnnotationIntrospector aiJaxb = new JaxbAnnotationIntrospector(TypeFactory.defaultInstance());
    AnnotationIntrospector aiJackson = new JacksonAnnotationIntrospector();
    mapper.setAnnotationIntrospector(AnnotationIntrospector.pair(aiJaxb, aiJackson));

    System.out.println(mapper.readValue(s, Response.class));

但是得到以下异常

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "entry" (class Entry), not marked as ignorable

at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:60)
at com.fasterxml.jackson.databind.DeserializationContext.handleUnknownProperty(DeserializationContext.java:822)
at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1152)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1567)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1545)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:293)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:151)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.handleNonArray(CollectionDeserializer.java:352)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.deserialize(CollectionDeserializer.java:264)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.deserialize(CollectionDeserializer.java:244)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.deserialize(CollectionDeserializer.java:27)
at com.fasterxml.jackson.databind.deser.impl.MethodProperty.deserializeAndSet(MethodProperty.java:127)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:287)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:151)
at com.fasterxml.jackson.databind.ObjectMapper._unwrapAndDeserialize(ObjectMapper.java:4081)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:3999)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2992)

......

不确定我错过了什么。任何帮助，将不胜感激。提前谢谢。

Answer 1

尝试添加此内容：

mapper.registerModule(new JaxbAnnotationModule());

@XmlElementWrapper和@ XmlElement无法使用Jackson

1 个答案: