Question

我有一个查询来获取某些列的计数。我得到输出没有错误，但我需要以不同的方式。有人可以帮我在Oracle Pl / SQL中获得以下输出吗？

SELECT   
SUM (DECODE(COLUMN1,'Y',1,0)) AS COUNT1,  
SUM (DECODE(COLUMN2,'Y',1,0)) AS COUNT2,  
SUM (DECODE(COLUMN3,'Y',1,0)) AS COUNT3,  
SUM (DECODE(COLUMN4,'Y',1,0)) AS COUNT4,  
SUM (DECODE(COLUMN5,'Y',1,0)) AS COUNT5,  
SUM (DECODE(COLUMN6,'Y',1,0)) AS COUNT6   
FROM TABLE_NAME  
WHERE COLUMN7 IN ('X','Y');

 **OUTPUT:**  
-----------------------------------------
COUNT1|COUNT2|COUNT3|COUNT4|COUNT5|COUNT6
-----------------------------------------
5500  | 1245 | 5245 | 5675 | 7845 | 5324
-----------------------------------------

**Required Output**

COUNT1 | 5500  
-------------
COUNT1 | 1245 
-------------
COUNT1 | 5245 
-------------
COUNT1 | 5675 
-------------
COUNT1 | 7845 
-------------
COUNT1 | 5324
-------------

Answer 1

使用UNION：

SELECT 'Count1' AS "Count", SUM (DECODE(COLUMN1,'Y',1,0)) AS Total 
FROM TABLE_NAME WHERE COLUMN7 IN ('X','Y')
UNION ALL
SELECT 'Count2' AS "Count", SUM (DECODE(COLUMN2,'Y',1,0)) AS Total 
FROM TABLE_NAME WHERE COLUMN7 IN ('X','Y')
UNION ALL
SELECT 'Count3' AS "Count", SUM (DECODE(COLUMN3,'Y',1,0)) AS Total 
FROM TABLE_NAME WHERE COLUMN7 IN ('X','Y')
UNION ALL
...

但是，如果您有一个group by列，则可以按其分组并在一个查询中使用该值。

<强>更新

您也可以使用UNPIVOT：

执行此操作

SELECT *
FROM
(
  SELECT   
  SUM (DECODE(COLUMN1,'Y',1,0)) AS COUNT1,  
  SUM (DECODE(COLUMN2,'Y',1,0)) AS COUNT2,  
  SUM (DECODE(COLUMN3,'Y',1,0)) AS COUNT3,  
  SUM (DECODE(COLUMN4,'Y',1,0)) AS COUNT4,  
  SUM (DECODE(COLUMN5,'Y',1,0)) AS COUNT5,  
  SUM (DECODE(COLUMN6,'Y',1,0)) AS COUNT6   
  FROM TABLE_NAME  
  WHERE COLUMN7 IN ('X','Y')
)
UNPIVOT
(
  Total
  FOR COL IN(COUNT1,COUNT2,COUNT3,COUNT4,COUNT5,COUNT6)
)

SQL Fiddle Demo

如何在Oracle PL SQL中将列名显示为行

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