Question

当我将参数传递为“09:30 AM”时，它会在android中返回异常显示无法解释的日期：“09:30 AM”（在偏移6处）

 public static String convertTo24Hour (String now){
        String time24="";
          try {
            SimpleDateFormat inFormat = new SimpleDateFormat("hh:mm a");
            SimpleDateFormat outFormat = new SimpleDateFormat("HH:mm");
            time24 = outFormat.format(inFormat.parse(now));
        } catch (Exception e) {
            System.out.println("Exception : " + e.getMessage());
        }
        return time24;
    }

Answer 1

试试这个

public static String convertTo24Hour (String now){
    String time24="";
    try {
        SimpleDateFormat inFormat = new SimpleDateFormat("hh:mm a",Locale.getDefault());
        SimpleDateFormat outFormat = new SimpleDateFormat("H:mm", Locale.getDefault());
        time24 = outFormat.format(inFormat.parse(now));
    } catch (Exception e) {
        System.out.println("Exception : " + e.getMessage());
    }
    return time24;
}

根据您的需要更改区域设置。希望这会有所帮助..

在java android中显示Unparseable日期：“09:30 AM”（在偏移6处）

1 个答案: