从PIC32MX移植到MZ(PIC32MZ2048EFG100)并且正在撞击墙壁试图在UART3上生成简单的RX中断。请参阅下面的代码。
void main(void} {
__builtin_disable_interrupts();
//Ensuring all pins config as digital
ANSELA = 0x0000;
ANSELB = 0x0000;
ANSELC = 0x0000;
ANSELD = 0x0000;
ANSELE = 0x0000;
ANSELF = 0x0000;
ANSELG = 0x0000;
//Convenient macrso to do IOUNLOCK
#define PPSUnLock() {SYSKEY=0x0;SYSKEY=0xAA996655;SYSKEY=0x556699AA;CFGCONbits.IOLOCK=0;}
#define PPSLock() {SYSKEY=0x0;SYSKEY=0xAA996655;SYSKEY=0x556699AA;CFGCONbits.IOLOCK=1;}
//Peripheral Pin Select (PPS) Settings for UART3
PPSUnLock();
U3RXRbits.U3RXR = 0b1010;
RPA14Rbits.RPA14R = 0b0001;
PPSLock();
//Config UART3
U3MODEbits.UEN0 = 0; //no flow control
U3MODEbits.UEN1 = 0;
U3MODEbits.LPBACK = 0; // no loopback
U3MODEbits.ABAUD = 0; //no autobaud
U3MODEbits.BRGH = 0;
U3MODEbits.PDSEL0 = 0; //8 data bits, no parity
U3MODEbits.PDSEL1 = 0;
U3MODEbits.STSEL = 0; // 1 stop bit
U3STAbits.URXISEL0 = 0; //RX Interrupt on first byte in FIFO
U3STAbits.URXISEL1 = 0;
U3BRG = CLOSEST_UBRG_VALUE115200; //Macro defined elsewhere, but it works
//Int priorities
IPC39bits.U3EIP = 6;
IPC39bits.U3EIS = 3;
//Int flags
IFS4bits.U3RXIF = 0;
//Int enable/disable
IEC4bits.U3EIE = 0;
IEC4bits.U3TXIE = 0;
IEC4bits.U3RXIE = 1; //Enable int on RX
//Enable multi-vector interrupts
INTCONSET = _INTCON_MVEC_MASK;
__builtin_enable_interrupts();
//Turn on UART3
U3STAbits.URXEN = 1;
U3STAbits.UTXEN = 1;
U3MODEbits.ON = 1;
UART_txEXTCOMandWait('A'); //Function defined elsewhere - I get successful byte "A" sent to my terminal. So TX works.
while(1){Nop();}; //wait in endless loop for interrupt to occur on keystroke
}
以下是我的ISR:
void __ISR_AT_VECTOR (_UART3_RX_VECTOR, IPL6SOFT) U3Interrupt(void) {
unsigned int test=0;
Nop(); //Setting a breakpoint here
}
我成功地看到了一个" A"在运行程序时在终端屏幕上,因此TX的设置正确。在终端屏幕中键入文本不会产生中断。已经验证信号正在进入PIC32。
我在这里缺少什么?我花了很多时间在一些应该是微不足道的事情上。
谢谢你们。
答案 0 :(得分:0)
想出来......应该是:
//Int priorities
IPC39bits.U3EIP = 6;
IPC39bits.U3EIS = 3;
多年来有趣的是PIC32MX的生产方式。