Question

我是php新手。我只想制作一个隐藏或取消隐藏div的按钮我在php块中放置了一个代码当我在php block.button中编写代码时不能正常工作; 当我在php块之外编码它然后它运行。为什么它不能在php块中运行？

<!DOCTYPE html>
    <html>
    <head>
        <title></title>
    </head>
    <body>
    <?php
    echo"<button onclick='myFunction('confession13')'>Comment</button>
    <div id='confession13'>
    <p>hlo world</p>
    </div>";
    ?>
    <script type="text/javascript">
    function myFunction(p1) 
    {   
        console.log(p1);
        var x = document.getElementById(p1);
        if (x.style.display === "none") 
        {
            x.style.display = "block";
        } 
        else {
            x.style.display = "none";
        }
    }
    </script>
    </body>
    </html>

Answer 1

<!DOCTYPE html>
    <html>
    <head>
        <title></title>
    </head>
    <body>
     <button onclick='myFunction("confession13")'>Comment</button>
     <div id='confession13'>
     <p>hlo world</p>
    </div>
    <script type="text/javascript">
    function myFunction(p1) 
    {   
        console.log(p1);
        var x = document.getElementById(p1);
        if (x.style.display === "none") 
        {
            x.style.display = "block";
        } 
        else {
            x.style.display = "none";
        }
    }
    </script>
    </body>
    </html>

当我在php块中编写切换代码时，它无法正常工作

1 个答案: