Question

当有on或condition时，我有左连接的本机sql查询，如何在查询构建器中表示它？

 $query = "  SELECT  te.id
            FROM    task_executions AS te
            INNER JOIN tasks AS t ON t.id = te.task_id
            LEFT JOIN cost_objects AS co ON co.id = t.cost_object_id
            LEFT JOIN cost_object_managers AS com ON com.cost_object_id = co.id OR com.cost_object_id = co.parent_id

我需要在查询构建器中表示它，但在User实体中我有ManyToMany关系，没有单独的表，当我尝试使用条件左连接时我有错误SingleValuedAssociationField expected.

用户实体

class User
{
...
/**
 * @ORM\ManyToMany(targetEntity="CostObject", mappedBy="users")
 */
private $costObjects;
}

CostObject实体

class CostObject
{
    /**
 * @var CostObject
 *
 * @ORM\ManyToOne(targetEntity="CostObject", inversedBy="children")
 * @ORM\JoinColumns({
 *   @ORM\JoinColumn(name="parent_id", referencedColumnName="id", onDelete="CASCADE")
 * })
 */
private $parent;

    /**
 * @var ArrayCollection
 *
 * @ORM\ManyToMany(targetEntity="User", inversedBy="costObjects")
 * @ORM\JoinTable(name="cost_object_managers",
 *      joinColumns={@ORM\JoinColumn(name="cost_object_id", referencedColumnName="id", onDelete="CASCADE")},
 *      inverseJoinColumns={@ORM\JoinColumn(name="user_id", referencedColumnName="id", onDelete="CASCADE")}
 * )
 */
private $users;

我的查询构建器没有条件

        $qb->select('te')
        ->from('AppBundle:TaskExecution', 'te')
        ->innerJoin('te.task', 't')

        ->leftJoin('t.costObject', 'co')
        ->leftJoin('co.users', 'com')

这是$query->getSQL()

SELECT some_name FROM task_executions t0_ INNER JOIN tasks t1_ ON t0_.task_id = t1_.id LEFT JOIN cost_objects c2_ ON t1_.cost_object_id = c2_.id LEFT JOIN cost_object_managers c4_ ON c2_.id = c4_.cost_object_id LEFT JOIN users u3_ ON u3_.id = c4_.user_id ORDER BY t0_.execution_start DESC

我需要像在nativbe查询中一样进行更改，但是当我向左连接添加条件时，我会收到错误

查询条件

        $qb->select('te')
        ->from('AppBundle:TaskExecution', 'te')
        ->innerJoin('te.task', 't')

        ->leftJoin('t.costObject', 'co')
        ->leftJoin(
            'co.users',
            'com',
            Join::WITH,
            $qb->expr()->orX
                (
                    'com.costObjects = co.id',
                    'com.costObjects = co.parent'
                )
            )

和错误

[Semantical Error] line 0, col 121 near 'costObjects =': Error: Invalid PathExpression. StateFieldPathExpression or SingleValuedAssociationField expected.

我尝试在回答

中添加IDENTITY

        ->leftJoin('t.costObject', 'co')
        ->leftJoin(
            'co.users',
            'com',
            Join::WITH,
            $qb->expr()->orX
                (
                    'IDENTITY(com.costObjects) = co.id',
                    'IDENTITY(com.costObjects) = co.parent'
                )
            )

但仍有错误

[Semantical Error] line 0, col 130 near 'costObjects)': Error: Invalid PathExpression. Must be a SingleValuedAssociationField.

Answer 1

试试这个：

$qb->select('te')
    ->from('AppBundle:TaskExecution', 'te')
    ->innerJoin('te.task', 't')

    ->leftJoin('t.costObject', 'co')
    ->leftJoin(
        'co.users',
        'com',
        Join::WITH,
        $qb->expr()->orX
            (
                'IDENTITY(com.costObjects) = co.id',
                'IDENTITY(com.costObjects) = co.parent'
            )
        )

查询生成器SingleValuedAssociationField预期

1 个答案: