Perl IPv6地址扩展/解析

时间:2011-01-26 01:38:49

标签: perl ipv6

我在标量中有一个类似2001:db8::1的地址,并希望获得扩展形式2001:0db8:0000:0000:0000:0000:0000:0001。主要的Perl软件包是否在/usr/lib/perl5/...的广阔森林中运送 - 一个已经可以执行此操作的模块?如果没有,有人会有几行会这样做吗?

2 个答案:

答案 0 :(得分:9)

CPAN Net::IP可以满足您的需求。

这是一份成绩单,显示了它的实际效果:

$ cat qq.pl
use Net::IP;
$ip = new Net::IP ('2001:db8::1');
print $ip->ip() . "\n";

$ perl qq.pl
2001:0db8:0000:0000:0000:0000:0000:0001

答案 1 :(得分:2)

Net::IP绝对是一个很好的方式,因为它简单而有力。但是,如果您要解析大量的问题,可以考虑使用inet_pton包中的Socket,因为它比Net::IP对象版本快10-20倍,即使是预先创建的对象。比ip_expand_address版快4倍:

use Net::IP;
use Time::HiRes qw(gettimeofday tv_interval);
use Socket qw(inet_pton AF_INET6);
use bignum;
use strict;

# bootstrap
my $addr = "2001:db8::1";
my $maxcount = 10000;

my $ip = new Net::IP($addr);

my ($t0, $t1);
my $res;

# test Net::IP
$t0 = [gettimeofday()];
for (my $i = 0; $i < $maxcount; $i++) {
    $ip->set($addr);
    $res = $ip->ip();
}
print "Net::IP elapsed:   " . tv_interval($t0) . "\n";
print "Net::IP Result:    $res\n";

# test non-object version
$t0 = [gettimeofday()];
for (my $i = 0; $i < $maxcount; $i++) {
    $res = Net::IP::ip_expand_address('2001:db8::1', 6);
}
print "ip_expand elapsed:  " . tv_interval($t0) . "\n";
print "ip_expand Result:   $res\n";

# test inet_pton
$t0 = [gettimeofday()];
for (my $i = 0; $i < $maxcount; $i++) {
    $res = join(":", unpack("H4H4H4H4H4H4H4H4",inet_pton(AF_INET6, $addr)));
}
print "inet_pton elapsed: " . tv_interval($t0) . "\n";
print "inet_pton result:  " . $res . "\n";

在我的随机机器上运行这个:

Net::IP elapsed:   2.059268
Net::IP Result:    2001:0db8:0000:0000:0000:0000:0000:0001
ip_expand elapsed: 0.482405
ip_expand Result:  2001:0db8:0000:0000:0000:0000:0000:0001
inet_pton elapsed: 0.132578
inet_pton result:  2001:0db8:0000:0000:0000:0000:0000:0001