Php内连接和显示结果

Question

我有2个数据库：

• 持有用户的一个
• 秒，其中包含用户的年度，月份，日期，日期ID。

在show.php

上

我有一个使用php运行的日历。我需要显示与日历具有相同日期的用户，如：

1. 用户1，用户2

3. 用户1

4. 用户2

等等。

private function _showDay($cellNumber){         
    if($this->currentDay==0){             
        $firstDayOfTheWeek = date('N',strtotime($this->currentYear.'-'.$this->currentMonth.'-01'));                     
        if(intval($cellNumber) == intval($firstDayOfTheWeek)){                
            $this->currentDay=1;                 
        }
    }
    if( ($this->currentDay!=0)&&($this->currentDay<=$this->daysInMonth) ){
        $this->currentDate = date('Y-m-d',strtotime($this->currentYear.'-'.$this->currentMonth.'-'.($this->currentDay)));
        $cellContent = $this->currentDay;
        $this->currentDay++;   
    }else{
        $this->currentDate =null;
        $cellContent=null;
    }    
    $conn = new mysqli('localhost', 'root', 'a', 'emp') 
    or die ('Cannot connect to db');
            $sqlday="SELECT emp.name, emp.id, tbl_data.id,tbl_data.year, tbl_data.month, tbl_data.date
                    FROM emp
                    INNER JOIN tbl_data ON emp.id = tbl_data.id 
                    WHERE tbl_data.year = $currentYear
                    AND tbl_data.month = $currentMonth 
                    AND tbl_data.date = $currentDate";
            $resultday = mysqli_query($conn,$sqlday);

    return '<p id="li-'.$this->currentDate.'" class="daycounts">'.$cellContent. ''.$resultday.'</p>';
}