我想要你的建议如果我更改下拉选择选项,那么我想更改我的表值,以便更好地了解我正在上传图片。谢谢
我正在上传我的控制器代码
public function index()
{
$allRoom =AllocateClassroom::with('course','department')->paginate(10);
//dd($allRoom);
return view('Admin.allocateClassrooms.index',['allRoom'=>$allRoom]);
}
这是我的观看代码
{{Form::label('department','Department')}}
<select name="department" id="department" class="form-control">
<option value=" ">----Select Department-----</option>
@foreach($allRoom as $value)
<option value="{{$value->id}}">{{$value->department->name}}</option>
@endforeach
</select>
<br>
<div class="table-responsive">
<table class="table table-bordered">
<tr class="success">
<th>ID</th>
<th>Course Code</th>
<th>Course Name</th>
<th>Schedule Info</th>
</tr>
<tr class="info" id="info">
<td class="success" >{{$value->id}}</td>
<td class="success" >{{$value->course->code}}</td>
<td class="success" >{{$value->course->name}}</td>
<td class="success" >{{$value-> Room_No}}
{{$value-> date}}
{{$value-> start_time}}
{{$value-> end_time}}
</td>
</tr>
</table>
</div>
答案 0 :(得分:1)
这就是我这样做的方式:
首先,我添加一个包装select的表单,这样当用户更改其值时,页面会重新加载选择的部门
<form method="get" id="department-form">
<select name="department" id="department" class="form-control" onchange="document.getElementById('department-form').submit()">
<option value=" ">----Select Department-----</option>
@foreach($allRoom as $value)
<option value="{{$value->id}}" @if($value->id == $department) selected @endif>{{$value->department->name}}</option>
@endforeach
</select>
</form>
在我的控制器中我会有这个:
public function index( Request $request)
{
$department = null;
if($request->department) $department = $request->department;
$allRoom =AllocateClassroom::with('course','department')->whereHas('department', function($query) use($department){
if($department) $query->where(id, $department);
})->paginate(10);
return view('Admin.allocateClassrooms.index',['allRoom'=>$allRoom, 'department' => $department]);
}
在这里,我从请求中获取我的部门并用它查询数据
<强>更新强>
抱歉,最后一段代码是让所有房间和符合条件的部门。现在它只获得符合部门条件的房间
答案 1 :(得分:0)
您正在尝试获取非对象的属性。在提供错误的文件中将{{$value->id}}
更改为{{$value['id']}}
。