Spring JPARepository更新字段

时间:2017-12-27 08:32:58

标签: spring hibernate spring-mvc spring-boot spring-data-jpa

我有一个简单的Java模型,名为Member with fields - ID(主键),Name(String),Position(String)

我想公开一个POST端点来更新成员的字段。这种方法可以接受像这样的有效载荷

{ "id":1,"name":"Prateek"}

{ "id":1,"position":"Head of HR"}

并根据收到的有效负载,我只更新该特定字段。如何使用JPARepository实现这一目标?

我的存储库界面是基本的 -

import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.stereotype.Repository;


@Repository("memberRepository")
public interface MemberRepository extends JpaRepository<Member, Integer>{

}

我的会员模特 -

@Entity
@Table(name="members")
public class Member {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name="member_id")
    private Integer id;

    @Column(name="member_name")
    @NotNull
    private String name;

    @Column(name="member_joining_date")
    @NotNull
    private Date joiningDate = new Date();

    @Enumerated(EnumType.STRING)
    @Column(name="member_type",columnDefinition="varchar(255) default 'ORDINARY_MEMBER'")
    private MemberType memberType = MemberType.ORDINARY_MEMBER;

    public Member(Integer id, String name, Date joiningDate) {
        super();
        this.id = id;
        this.name = name;
        this.joiningDate = joiningDate;
        this.memberType = MemberType.ORDINARY_MEMBER;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Date getJoiningDate() {
        return joiningDate;
    }

    public void setJoiningDate(Date joiningDate) {
        this.joiningDate = joiningDate;
    }

    public MemberType getMemberType() {
        return memberType;
    }

    public void setMemberType(MemberType memberType) {
        this.memberType = memberType;
    }

    public Member(String name) {
        this.memberType = MemberType.ORDINARY_MEMBER;
        this.joiningDate = new Date();
        this.name = name;
    }

    public Member() {

    }

}

1 个答案:

答案 0 :(得分:2)

这样的事情可以解决问题

public class MemberService {

  @Autowired
  MemberRepository memberRepository;

  public Member updateMember(Member memberFromRest) {

    Member memberFromDb = memberRepository.findById(memberFromRest.getid());

    //check if memberFromRest has name or position and update that to memberFromDb

    memberRepository.save(memberFromDb);
  }
}