我试图遍历在随机元素中有标签的表单,并检查标签是否与给定的标签名称匹配,如果匹配,我正在为该元素添加一个类。但我无法让它工作,我该怎么做?
这是我尝试过的。
在div
之类的随机元素中包含标签的表单<form id="grtform">
<div id="section-1">
<lable>Currency type</lable>
<input type="text" name="currencyType">
</div>
<div id="section-2">
<lable>Currency rate</lable>
<input type="text" name="currencyRate">
</div>
<lable>Currency of country</lable>
<input type="text" name="currencyCountry">
<div id="section-3">
<div class="formData">
<lable>Currency due</lable>
<input type="text" name="currencyDue">
</div>
</div>
</form>
Jquery代码:
$("#grtform").each(function(){
var matchLable = "Currency due"
var lable = $(this).find('label').text();
if(matchLable == lable){
$(this).addClass('matchFound');
}
});
答案 0 :(得分:5)
你需要循环通过标签,而不是形式
$("#grtform lable").each(function(){ // selecting all labels of form
var matchLable = "Currency type"
var lable = $(this).text(); // changed here too
if(matchLable == lable){
$(this).addClass('matchFound');
}
});
在上面的代码中,这指的是当前迭代标签。
稍微修剪一下
$("#grtform lable").each(function(){ // selecting all labels of form
if($(this).text() == "Currency type"){
$(this).addClass('matchFound');
}
});
答案 1 :(得分:0)
您还可以使用以下方式: -
var allLables = document.querySelectorAll("#grtform lable");
for(var i = 0; i < allLables.length; i++){
var matchLable = "Currency type";
var lable = allLables[i].innerText; // changed here too
if(matchLable == lable){
allLables[i].classList.add("matchFound");
}
}
<form id="grtform">
<div id="section-1">
<lable>Currency type</lable>
<input type="text" name="currencyType">
</div>
<div id="section-2">
<lable>Currency rate</lable>
<input type="text" name="currencyRate">
</div>
<lable>Currency of country</lable>
<input type="text" name="currencyCountry">
<div id="section-3">
<div class="formData">
<lable>Currency due</lable>
<input type="text" name="currencyDue">
</div>
</div>
</form>