Question

1

json_obj = response.json()
az = []
for item in json_obj['DATA']['data']:
    az.append(item['name'])
print (az)

第1号代码结果是这个

['Australia', 'CHINA', 'Combodia', 'EUROPE', 'HONG KONG', 'INDIA',         
'INDONESIA', 'JAPAN', 'KOREA', 'MALAYSIA', 'Myanmar', 'New Zealand', 
'PHILIPPINES', 'Russia', 'senchilles', 'SINGAPORE', 'Sri Lanka', 'TAIWAN', 
'TestCountry', 'THAILAND', 'UNITED KINGDOM', 'USA', 'Vietnam', 'XY Test 
Country']

然后我添加此代码

2

for i in az:
     print(az.index(i) +1, end=' ')
     print(" ",i)

，结果代码2就像这样

1   Australia
2   CHINA
3   Combodia
4   EUROPE
5   HONG KONG
6   INDIA
7   INDONESIA
8   JAPAN
9   KOREA
10   MALAYSIA
11   Myanmar
12   New Zealand
13   PHILIPPINES
14   Russia
15   senchilles
16   SINGAPORE
17   Sri Lanka
18   TAIWAN
19   TestCountry
20   THAILAND
21   UNITED KINGDOM
22   USA
23   Vietnam
24   XY Test Country

我的问题是如何将代码2的结果插入到一个变量中，以便我可以像下面一样调用'az'列表

reply = az
response.status = falcon.HTTP_200
response.body = self.format_message(message,reply)

Answer 1

az = ['Australia', 'CHINA', 'Combodia', 'EUROPE', 'HONG KONG', 'INDIA',         
'INDONESIA', 'JAPAN', 'KOREA', 'MALAYSIA', 'Myanmar', 'New Zealand', 
'PHILIPPINES', 'Russia', 'senchilles', 'SINGAPORE', 'Sri Lanka', 'TAIWAN', 
'TestCountry', 'THAILAND', 'UNITED KINGDOM', 'USA', 'Vietnam', 'XY Test 
Country']

s='\n'.join("{}\t{}".format(*x) for x in enumerate(az, start=1))

print(s)

1       Australia
2       CHINA
3       Combodia
4       EUROPE
5       HONG KONG
6       INDIA
7       INDONESIA
8       JAPAN
9       KOREA
10      MALAYSIA
11      Myanmar
12      New Zealand
13      PHILIPPINES
14      Russia
15      senchilles
16      SINGAPORE
17      Sri Lanka
18      TAIWAN
19      TestCountry
20      THAILAND
21      UNITED KINGDOM
22      USA
23      Vietnam
24      XY Test Country

Answer 2

字符串连接可以用于此。

x = ''
for i in az:
  x += str(az.index(i) + 1)+'\t'+i+'\n'
print(x)

x拥有24个国家的完整字符串。

如何合并这两个Python列表代码？

2 个答案: