我有两个html用于左侧图像&内容和右侧图像&内容。从模型打印的价值。我可以写什么 - 每个循环在模型页面的局部视图中交替打印奇数和偶数值。
@inherits UmbracoViewPage<List<ProjectName.Models.DealerSectionModel>>
@using ProjectName.Models;
@using Umbraco.Core;
@{
foreach (DealerSectionModel historylist in Model) // what should i write in this loop .(ex if 1 value in model then print odd html)
{
if ()
{
@RenderEvenHistoryList(historylist)
}
else
{
@RenderOddHistoryList(historylist)
}
}
}
@helper RenderOddHistoryList(DealerSectionModel item)
{
<div class="row history-second-section py-2 py-xl-4 py-lg-4 py-md-4 py-sm-2">
<div class="col-12 col-xl-6 col-lg-6 col-md-6 col-sm-12 history-second-images">
<div class="quote my-3"><iframe src="@item.VideoUrl" width="510" height="282" frameborder="0" allowfullscreen></iframe></div>
</div>
<div class="col-12 col-xl-6 col-lg-6 col-md-6 col-sm-12 history-second-content">
<div class="content-year">@item.Title </div>
<h4>@item.ImageTitle</h4>
<p>@item.ImageDescription</p>
</div>
</div>
}
}
@helper RenderEvenHistoryList(DealerSectionModel item)
{
// render html for even model value
}
}
&#13;
答案 0 :(得分:3)
我对umbraco不太了解,但为什么不尝试像
这样简单的事情 @{
var even = false;
foreach (DealerSectionModel historylist in Model) // what should i write in this loop .(ex if 1 value in model then print odd html)
{
if (even)
{
@RenderEvenHistoryList(historylist)
}
else
{
@RenderOddHistoryList(historylist)
}
even = !even;
}
}
答案 1 :(得分:1)
你可以这样做
@ {int count = 1;
foreach (DealerSectionModel historylist in Model)
{
if (count % 2 == 0)
{
@RenderEvenHistoryList(historylist)
}
else
{
@RenderOddHistoryList(historylist)
}
count++;
}
}