我们使用我们的密钥构建了一个API来直接访问其他社交网络API。
我正在尝试构建一个功能来访问该API。
默认功能已写入并正在运行。
问题
function SocialAPI($handle, $service, $path="") {
$handle = strtolower($handle);
$service = strtolower($service);
$api = file_get_contents("https://api.service.domain.com/v1/Social?handle=$handle&service=$service");
if($api !== false) {
$data = json_decode($api, true);
if($data !== null) {
if($service === "twitter") {
return $data['0']['followers_count'];
}
if($service === "instagram") {
if(!empty($path)) {
while($id = array_shift($path)) {
echo $data[$id];
}
return $data;
} else {
return $data['user']['followed_by']['count'];
}
}
} else {
return false;
}
} else {
return "API call failed.";
}
}
//Test API Function - ** TO BE DELETED **
echo SocialAPI("JohnDoe", "Instagram", "['user']['full_name']");
exit();
答案 0 :(得分:0)
function array_deref($data, $keys) {
return empty($keys) ? $data
: array_deref($data[$keys[0]], array_slice($data, 1))
}
function SocialAPI($handle, $service, $path="") {
$handle = strtolower($handle);
$service = strtolower($service);
$api = file_get_contents("https://api.service.domain.com/v1/Social?handle=$handle&service=$service");
if ($api === false) {
return "API call failed.";
}
$data = json_decode($api, true);
if($data !== null) {
return false;
}
if ($service === "twitter") {
if (empty($path)) $path = ['0','followers_count'];
return array_deref($data, $path);
} elseif ($service === "instagram") {
if (empty($path)) $path = ['user','followed_by'];
return array_deref($data, $path);
}
}
//Test API Function - ** TO BE DELETED **
echo SocialAPI("JohnDoe", "Instagram", ['user', 'full_name']);
echo SocialAPI("JohnDoe", "Instagram");
exit();
我添加了一个实用程序函数array_deref
,以递归方式遍历数组(调用自身来处理每个级别)。