我在Angularjs Grid中获取了一组数据,我需要删除所有具有相同CustCountry的行
ex - 我的客户数组看起来像
Customer[0]={ CustId:101 ,CustName:"John",CustCountry:"NewZealand" };
Customer[1]={ CustId:102 ,CustName:"Mike",CustCountry:"Australia" };
Customer[2]={ CustId:103 ,CustName:"Dunk",CustCountry:"NewZealand" };
Customer[3]={ CustId:104 ,CustName:"Alan",CustCountry:"NewZealand" };
因此,在网格中,如果CustomerCountry是NewZealand
,我需要删除所有三条记录我正在使用拼接方法,让我知道如何通过CustomerCountry拼接来使用
$scope.remove=function(CustCountry)
{
$scope.Customer.splice(index,1);
}
答案 0 :(得分:2)
如果您对收回副本没问题,这是.filter
的完美用例:
Customer = [
{ CustId:101 ,CustName:"John",CustCountry:"NewZealand" },
{ CustId:102 ,CustName:"Mike",CustCountry:"Australia" },
{ CustId:103 ,CustName:"Dunk",CustCountry:"NewZealand" },
{ CustId:104 ,CustName:"Alan",CustCountry:"NewZealand" },
]
console.log(Customer.filter(cust => cust.CustCountry !== "NewZealand"));
答案 1 :(得分:0)
如果您考虑到某个特定国家/地区,请使用.filter()
$scope.Customer = $scope.Customer.filter(obj => obj.CustCountry !== "SpecificCountry")
如果您要删除所有包含重复国家/地区的对象,请参阅Remove duplicate values from JS array,这是您可以执行的操作:
var removeDuplicateCountries = function(arr){
var dupStore = {};
for (var x= 0; x < arr.length; x++){
if (arr[x].CustCountry in dupStore){
dupStore[arr[x].CustCountry] = false;
} else {
dupStore[arr[x].CustCountry] = true;
}
}
var newarr = [];
for (var x= 0; x < arr.length; x++){
if (dupStore[arr[x].CustCountry]){
newarr.push(arr[x]);
}
}
return arr;
};
$scope.Customer = removeDuplicateCountries($scope.Customer);
或合并.filter()方法
var removeDuplicateCountries = function(arr){
var dupStore = {};
var newarr = arr;
for (var x= 0; x < arr.length; x++){
if (arr[x].CustCountry in dupStore){
newarr = newarr.filter(obj => obj.CustCountry !== arr[x].CustCountry);
} else {
dupStore[arr[x].CustCountry] = true;
}
}
return newarr;
};
$scope.Customer = removeDuplicateCountries($scope.Customer);
如果有许多重复的国家/地区,请使用不带.filter()
的方式