我让Jquery从db读取数据,当我点击列表时,它会在详细信息框中显示roe数据。 但是....问题:我在显示内容的地方制作div。我用Jquery加载页面到div。 但是当我这样做时,行点击不起作用。我无法理解为什么。它是shild元素,但是当我使用getElementById它应该接受当前行但是没有时,我正在知道它。
<!DOCTYPE html>
<!--
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and open the template in the editor.
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<?php include './config/init.php'; ?>
<html>
<head>
<meta charset="UTF-8">
<title>Biisilista</title>
<script src="./js/jquery-3.2.1.js"></script>
<link href="css/basic.css" rel="stylesheet" type="text/css">
</head>
<body>
<h1>KaraokeBiisit </h1>
<div id="edit" style="display:none">
<div>
<form name="formedit" method="post" action="">
<table id="edittable" border="1" cellspacing="2" cellpadding="1">
<tbody>
<tr>
<td>
<label>Nimi:</label>
</td>
<td>
<input id="nimi" name="nimi" placeholder="Kappaleen nimi" type="text">
</td>
<td>
<label>Levy:</label>
</td>
<td>
<input id="levy" name="levy" placeholder="Levyn tunnus" type="text" width="10px">
</td>
</tr>
<tr>
<td>
<label>Artisti:</label>
</td>
<td>
<input id="artisti" name="artisti" placeholder="Kappaleen esittäjä" type="text">
</td>
<td>
<label>Kieli:</label>
</td>
<td>
<input id="kieli" name="kieli" placeholder="Alkuperäiskieli" type="text" width="20">
</td>
</tr>
<tr>
<td>
<label>Numero:</label>
</td>
<td>
<input id="numero" name="numeron" placeholder="Numero" type="text">
</td>
</tr>
</tbody>
</table>
</form>
</div>
</div>
<div id="pageContent">
</div>
<script src="./js/jquery-3.2.1.js"></script>
<script src="./js/script.js"></script>
</body>
</html>
jQuery(document).ready(function ($) {
$("#pageContent").click(function () {
$('tr').removeClass('selected');
$(this).addClass('selected');
var selectedRow;
selectedRow = $(rivi);
var td = $(selectedRow).children('td');
$('#nimi').val(td[0].innerText);
$('#artisti').val(td[1].innerText);
$('#levy').val(td[2].innerText);
$('#kieli').val(td[3].innerText);
$('#numero').val(td[4].innerText);
console.log("test");
});
$(".clickable-row").on('click', () => {
$('#edit').show();
});
$('#pageContent').load('container.php');
// $('#pageContent').load('biisit.php');
});
function showBiisit() {
console.log("Näytetään sisältö");
$('#pageContent').load('container.php');
}
<?php include './config/init.php'; ?>
<?php
//luodaan tietokantaobjekti
$db = new DataBase();
// tehdään kysely
$db->query("SELECT * FROM kappaleet");
//query("SELECT `id`,`nimi`,`artisti`,`levy`,`kieli`,`numero` FROM `kappaleet`;");
//yhdistetään hakutulokseen
$kappaleet = $db->resultset();
?>
<table id="dataTable">
<tr>
<th>Nimi</th>
<th>Artisti</th>
<th width="100" align="left">Levy</th>
<th width="100" align="left">Kieli</th>
<th width="100" align="left">Numero</th>
</tr>
<?php foreach ($kappaleet as $biisi): ?>
<tr class='clickable-row' >
<td><?php echo $biisi->nimi ?></td>
<td><?php echo $biisi->artisti ?></td>
<td><?php echo $biisi->levy ?></td>
<td><?php echo $biisi->kieli ?></td>
<td><?php echo $biisi->numero ?></td>
</tr>
<?php endforeach; ?>
</table>
答案 0 :(得分:0)
试试这个
...
$("body").on('click', '.clickable-row', function () { //i change this line
$('tr').removeClass('selected');
$(this).addClass('selected');
var selectedRow = $(this);
//selectedRow = $(rivi); idk what is this
var td = selectedRow.children('td');
$('#nimi').val(td[0].innerText);
$('#artisti').val(td[1].innerText);
$('#levy').val(td[2].innerText);
$('#kieli').val(td[3].innerText);
$('#numero').val(td[4].innerText);
console.log("test");
});
...