我有一些代码为回调处理程序定义了一个匿名内部类。这个处理程序需要分配一个局部变量,见下文。我需要在回调中分配resp
并在函数末尾引用它。我在Eclipse中遇到了这个错误:
无法分配最终的局部变量resp
,因为它是在封闭类型中定义的
我该如何解决这个问题?
DoorResult unlockDoor(final LockableDoor door) {
final UnlockDoorResponse resp;
final boolean sent = sendRequest(new UnlockDoorRequest(door),
new ResponseAction() {
public void execute(Session session)
throws TimedOutException, RetryException, RecoverException {
session.watch(UNLOCK_DOOR);
resp = (UnlockDoorResponse)session.watch(UNLOCK_DOOR);
}
});
DoorResult result;
if (!sent) {
return DoorResult.COMMS_ERROR;
}
else {
return DoorResult.valueOf(resp.getResponseCode());
}
}
答案 0 :(得分:5)
这是一个适合您案例的黑客攻击:
DoorResult unlockDoor(final LockableDoor door) {
final UnlockDoorResponse resp[] = { null };
final boolean sent = sendRequest(new UnlockDoorRequest(door), new ResponseAction() {
public void execute(Session session) throws TimedOutException, RetryException, RecoverException {
session.watch(UNLOCK_DOOR);
resp[0] = (UnlockDoorResponse)session.watch(UNLOCK_DOOR);
}
});
DoorResult result;
if (!sent) {
return DoorResult.COMMS_ERROR;
}
else {
return null == resp[0] ? null : DoorResult.valueOf(resp[0].getResponseCode());
}
}
但是,如果您需要更清晰的解决方案,则必须为处理程序定义命名类,将响应存储在其字段中,并使用访问器方法检索它。
祝你好运, 斯坦。
答案 1 :(得分:3)
你可以通过为响应创建一个包装类来解决这个问题。
class ResponseWrapper {
UnlockDoorResponse resp;
void setResponse(UnlockDoorResponse resp) {
this.resp = resp;
}
UnlockDoorResponse getResponse() {
return resp;
}
}
然后,您的代码将如下所示:
final ResponseWrapper respWrap = new ResponseWrapper();
final boolean sent = sendRequest(new UnlockDoorRequest(door), new ResponseAction() {
public void execute(Session session) throws TimedOutException, RetryException, RecoverException {
session.watch(UNLOCK_DOOR);
respWrap.setResponse((UnlockDoorResponse)session.watch(UNLOCK_DOOR));
}
});
DoorResult result;
if (!sent) {
return DoorResult.COMMS_ERROR;
}
else {
return DoorResult.valueOf(respWrap.getResponse().getResponseCode());
}
答案 2 :(得分:1)
假设这是您要更改的代码,请如何更改sendRequest
和ResponseAction.execute
以返回UnlockDoorResponse
的实例
DoorResult unlockDoor(final LockableDoor door) {
final UnlockDoorResponse resp = sendRequest(new UnlockDoorRequest(door), new ResponseAction() {
public UnlockDoorResponse execute(Session session) throws TimedOutException, RetryException, RecoverException {
session.watch(UNLOCK_DOOR);
return (UnlockDoorResponse)session.watch(UNLOCK_DOOR);
}
});
if (resp == null) {
return DoorResult.COMMS_ERROR;
}
else {
return DoorResult.valueOf(resp.getResponseCode());
}
}
答案 3 :(得分:0)
如果要返回结果,则使用命名的内部类而不是匿名内部类。所有其他选项都是恕我直言,丑陋的黑客(一个自我承认; - )
(好的,@ Joel不是,但假设您可以更改正在实施的界面)
只需使用getter为结果创建一个类的实例,它就是干净的,只需要你实现单个类。
class MyReponseAction implements ResponseAction {
private UnlockDoorResponse response;
public void execute(Session session) throws TimedOutException, RetryException, RecoverException {
session.watch(UNLOCK_DOOR);
response = (UnlockDoorResponse)session.watch(UNLOCK_DOOR);
}
UnlockDoorResponse getResponse() {
return response;
}
}
DoorResult unlockDoor(final LockableDoor door) {
ResponseAction action = new MyResponseAction();
final boolean sent = sendRequest(new UnlockDoorRequest(door), action);
DoorResult result;
if (!sent) {
return DoorResult.COMMS_ERROR;
}
else {
return DoorResult.valueOf(action.getResponse().getResponseCode());
}
}