在Console中创建“3D”立方体并旋转它(掷骰子样式)有什么好算法?
我们将不胜感激。
答案 0 :(得分:4)
我不知道这是否有资格作为您正在寻找的“算法”,但您可以随时进行完整的3D计算。
绘制立方体线框的示例代码(我使用OpenTK中的Vector / Matrix类,您也可以从XNA或其他库中获取它们)
using System;
using System.Linq;
using OpenTK;
class Cubes
{
static void Main() {
var resolution = 25;
var points = from i in Enumerable.Range(1, 8) select new Vector3(i / 4 % 2 * 2 - 1, i / 2 % 2 * 2 - 1, i % 2 * 2 - 1);
var lines = from a in points
from b in points
where (a - b).Length == 2 // adjacent points
&& a.X + a.Y + a.Z > b.X + b.Y + b.Z // select each pair once
select new { a, b };
var t = 0f;
while (true) {
t += .1f;
var projection = Matrix4.CreatePerspectiveFieldOfView(.8f, 1, .01f, 100f);
var view = Matrix4.LookAt(2 * new Vector3((float)Math.Sin(t), .5f, (float)Math.Cos(t)), Vector3.Zero, Vector3.UnitY);
Console.Clear();
foreach (var line in lines) {
for (int i = 0; i < resolution; i++) {
var point = (1f / resolution) * (i * line.a + (resolution - 1 - i) * line.b); // interpolate a point between the two corners
var p1 = 5 * Vector3.Transform(point, view * projection) + new Vector3(30, 20, 0);
Console.SetCursorPosition((int)p1.X, (int)p1.Y);
Console.Write("#");
}
}
Console.ReadKey();
}
}
}
输出中的示例帧:
# ###### #### # ## #### # ## #### # ## ### # ## ## # ### ### # ## # ## # ## # ## # ### # ## # ### # # ## # ### # # ## ##### # # ## ### # # ##### # # # # # # # # # # # # # # # # # # # # # # # # # # # # ##### # # ### ## # # ##### ## # # ### # ## # # ### # ## # ### # ## # ## # ## # ## # ### ### # ## ## # ### ## # #### ## # #### ## # #### ###### # # ###### ## # ### ## # ### ## # #### ## # #### ## # ## ## # ### # # ## # ## # ## # # #### # ## # # #### # # # # #### ## # # ##### ## # # # #### # # # # # # # # # # # # # # # # # # # # # # # # # # #### # # # ## ##### # # ## #### # # # # #### # # ## # #### # # ## # ## # ## # # ### # ## ## # ## #### # ## #### # ## ### # ## ### # ## ###### # # ############## # ########## ## ## ## ## ### ### # # # # # # # # ## # ## # # # # # ## # # # ############## # # # # ########## # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # ########## # # # # ############## # # # ## # # # # # ## # ## # # # # # # # # ### ### ## ## ## ## ########## # ############## #
答案 1 :(得分:1)
我认为没有一个好的“3D立方体ascii艺术算法”。我只想使用3D立方体动画 - 您可以在设计时或运行时创建它 - 并使用普通的ASCII艺术生成器。
答案 2 :(得分:0)
你可以创建一个while循环,它显示一个字符数组,生成立方体的3D ascii动画,直到你希望它停止。使用foreach (char spinCube in spinCubeTest)
之类的东西来相应地移动字符。