Question

我试图通过比较2个对象来创建一个对象，如果有相同的id，那么创建一个对象。

例如：

obj1 = [{"id":1,"name":"john"},{"id":2,"name":"kile"},{"id":3,"name":"kenny"},
{"id":4,"name":"stan"}]

obj2 = [{"id":1,"name":"dan"},{"id":1,"name":"ben"},{"id":1,"name":"sarah"},
{"id":2,"name":"kelly"}]

我正在寻找的结果是：

result = [{1:{"id":1,"name":"john"},{"id":1,"name":"dan"},
    {"id":1,"name":"ben"},{"id":1,"name":"sarah"},

 //both objects from obj1 & obj 2 which holds the same ID are now in new 
  object "1" - which is the id that's common to them//

{2:{{"id":2,"name":"kile"},
{"id":2,"name":"kelly"}}}]

更明确：

在两个匹配id＆＃39; s
将它们堆叠在一个对象中...所以新对象将包含来自它们的匹配id对象....

我试过了：

var obj_names_1 = [{"id":1,"name":"john"},{"id":2,"name":"kile"},
{"id":3,"name":"kenny"},
{"id":4,"name":"stan"}];

var obj_names_2 = [{"id":1,"name":"dan"},{"id":1,"name":"ben"},
{"id":1,"name":"sarah"},
{"id":2,"name":"kelly"}];

 function getMessages(obj1, obj2){
    var messages_tab = [];
    $.each(obj1, function(){

        var messages_wrap = this;
        var recieved_messages_id = this.id;
        $.each(obj2, function(){
            var sent_messages_id = this.id;
            if(recieved_messages_id == sent_messages_id){


                messages_tab.push({1:[this,messages_wrap]}); // key 0 should 
                be the common id

            }

        });
    });
    return messages_tab;
}

console.log(getMessages(obj_names_1,obj_names_2));

但这里的第一个问题是它没有超过1个结果

Fiddle

Answer 1

您可以array#concat两个阵列，然后使用array#reduce推送具有相同id的数组中的对象。

注意：与id对应的值应为数组。

var obj1 = [{"id":1,"name":"john"},{"id":2,"name":"kile"},{"id":3,"name":"kenny"},{"id":4,"name":"stan"}],
    obj2 = [{"id":1,"name":"dan"},{"id":1,"name":"ben"},{"id":1,"name":"sarah"},{"id":2,"name":"kelly"}]
    result = obj1.concat(obj2).reduce((r,o) => {
      r[o.id] = r[o.id] || [];
      r[o.id].push(o);
      return r;
    },{});

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

如何通过2个对象的相同值创建对象？

1 个答案: