我在我的python代码中使用了一个选择器从Soccer: Next To Play
中获取html elements
。当我使用for loop
和.extract()
不需要的部分时,它工作正常。但是,有没有更好的方法从上面的元素中获取上述文本,或者至少使用单行表达式来执行相同的操作。
from bs4 import BeautifulSoup
content='''
<div class="page-title-new">
<h1>
Soccer: Next To Play
<span aria-hidden="true" class="race-large ng-hide" ng-show="vm.hasRaceNumber()">
RACE
</span>
<span aria-hidden="true" class="race-small ng-hide" ng-show="vm.hasRaceNumber()">
R
</span>
<span aria-hidden="true" class="ng-hide" ng-show="vm.hasRaceNumber()">
</span>
</h1>
<div aria-hidden="true" class="page-info-new ng-hide" ng-show="vm.hasEventDetailItems()">
<!-- -->
</div>
</div>
'''
soup = BeautifulSoup(content,"lxml")
for item in soup.select(".page-title-new h1"):
for elem in item.select("span"):elem.extract()
print(item.text.strip())
# items = [item.text for item in soup.select(".page-title-new h1")] #what to do to finish it as a one-liner
# print(items)
循环得到的东西(这是我想要的,没有循环或单行代码):
Soccer: Next To Play
没有循环我得到的东西:
Soccer: Next To Play RACE R
答案 0 :(得分:1)
使用soup.select_one()
方法(仅查找与CSS选择器匹配的第一个标记):
...
soup = BeautifulSoup(content,"lxml")
result = soup.select_one(".page-title-new > h1").contents[0].strip()
print(result)
输出:
Soccer: Next To Play