Question

大家好我如何选择所有第二个最后一笔交易。

交易日志

------------------------------
ID|MemberName|TransactionDate|
------------------------------
1 |Member 1  |1/1/2017       |
------------------------------
2 |Member 1  |1/2/2017       | <- I want to select this transaction
------------------------------
3 |Member 1  |1/3/2017       |This the last transaction of this client
------------------------------
4 |Member 2  |2/1/2017       |
------------------------------
5 |Member 2  |2/2/2017       |<- I want to select this transaction
------------------------------
6 |Member 2  |2/3/2017       |This the last transaction of this client

我想选择所有客户的所有第二个到最后一笔交易。

Answer 1

尝试ROW_NUMBER()功能（除非您使用MySQL）。

SELECT A.ID, A.MEMBERNAME, A.TRANSACTIONDATE
FROM
(
SELECT ID, MEMBERNAME, TRANSACTIONDATE, ROW_NUMBER() OVER (PARTITION BY MEMBERNAME ORDER BY TRANSACTIONDATE DESC) AS RNUM
FROM  TRANSACTION_TABLE
) A
WHERE A.RNUM = 2;

它为每种类型的Membername中的所有条目创建索引，并按降序排序编号（意味着第一个索引代表最新的transactiondate）。在此索引列中，您可以为第二个最后一个transactiondate提供rnum = 2的过滤器。

Answer 2

Select top(1) a.Id,a.MemberName, a.TransactionDate from (select top(2) Id,MemberName,TransactionDate from Transaction_log order by Id desc) as a order by a.Id asc;

假设表名为Transaction_Log。我希望这对你有用。

Answer 3

我刚刚使用聚合和加入，如下面的查询所示：

SELECT A.* FROM TRANSACTION_LOG A INNER JOIN 
(SELECT MEMBER_NAME, MAX(ID) ID FROM TRANSACTION_LOG
GROUP BY MEMBER_NAME) B 
ON A.MEMBER_NAME=B.MEMBER_NAME AND A.ID=B.ID-1;

这是SQL Fiddle DEMO

如何选择所有第二个到最后一个交易

3 个答案: