Question

这是我的SignUp Acitivity。我尝试使用Firebase创建createUserWithEmailAndPassword，并在用户的个人资料中添加一些详细信息，例如全名，地址和电话号码。我想在＆＃34;用户＆＃34;中添加唯一ID下的用户个人资料。使用电子邮件和密码创建用户时分配给新用户的数据库。

public void signUpButtonClicked(View view) {

    if (!TextUtils.isEmpty(email_text) && !TextUtils.isEmpty(pass_text)) {
        mAuth.createUserWithEmailAndPassword(email_text, pass_text).addOnCompleteListener(new OnCompleteListener<AuthResult>() {

            public void onComplete(@NonNull Task<AuthResult> task) {
                if (task.isSuccessful()) {
                    String user_id = mAuth.getCurrentUser().getUid();
                    DatabaseReference current_user = mDatabase.child(user_id);
                    current_user.child("Email").setValue(email_text);
                    current_user.child("Full name").setValue(fullName);
                    current_user.child("Nickname").setValue(nick);
                    current_user.child("Address").setValue(fullAdd);
                    current_user.child("Phone Number").setValue(phone);

                    Toast.makeText(MainActivity.this, "You are now REGISTERED", Toast.LENGTH_LONG).show();
                    Intent userProfile = new Intent(MainActivity.this, MenuActivity.class);
                    startActivity(userProfile);

                } else {
                    email.setError(null);
                    pass.setError(null);
                }
            }
        });
   }

这就是我的 build.gradle 的样子。

dependencies {
    implementation fileTree(include: ['*.jar'], dir: 'libs')
    implementation 'com.android.support:appcompat-v7:26.1.0'
    implementation 'com.android.support.constraint:constraint-layout:1.0.2'
    implementation 'com.google.firebase:firebase-auth:11.8.0'
    implementation 'com.google.firebase:firebase-database:11.8.0'
    testImplementation 'junit:junit:4.12'
    androidTestImplementation 'com.android.support.test:runner:1.0.1'
    androidTestImplementation 'com.android.support.test.espresso:espresso-core:3.0.1'
    implementation 'com.android.support:recyclerview-v7:26.1.0'
    compile 'com.squareup.picasso:picasso:2.5.2'
    compile 'com.firebaseui:firebase-ui-database:1.0.1'
    implementation 'com.android.support:cardview-v7:26.1.0'
    compile 'com.cepheuen.elegant-number-button:lib:1.0.2'

    compile 'com.amulyakhare:com.amulyakhare.textdrawable:1.0.1'
    compile 'com.readystatesoftware.sqliteasset:sqliteassethelper:+'
}
apply plugin: 'com.google.gms.google-services'

它并没有崩溃，但它也没有做任何事情。它只记录了这个错误。

12-26 12:12:53.194 4484-4522/com.example.example.example W/BiChannelGoogleApi: [FirebaseAuth: ] getGoogleApiForMethod() returned Gms
12-26 12:12:56.766 4484-4484/com.example.example.example  W/BiChannelGoogleApi: [FirebaseAuth: ] getGoogleApiForMethod() returned Gms
12-26 12:12:57.943 4484-4522/com.example.example.example  W/BiChannelGoogleApi: [FirebaseAuth: ] getGoogleApiForMethod() returned Gms
12-26 12:13:03.621 4484-4522/com.example.example.example W/BiChannelGoogleApi: [FirebaseAuth: ] getGoogleApiForMethod() returned Gms
12-26 12:13:11.635 4484-4522/com.example.example.example W/BiChannelGoogleApi: [FirebaseAuth: ] getGoogleApiForMethod() returned Gms

Answer 1

尝试在手机或模拟器中降级Firebase版本或更新Goole播放和播放服务。

implementation 'com.google.firebase:firebase-auth:11.4.2'
implementation 'com.google.firebase:firebase-database:11.4.2'
implementation 'com.firebaseui:firebase-ui-database:3.1.0'

或Firebase版本 10.2.6

Firebase错误：W / BiChannelGoogleApi：[FirebaseAuth：] getGoogleApiForMethod（）返回Gms

1 个答案: