Question

这是我的问题here的后续跟进：我在 uzi 提供的问题中得到了很好的答案。然而，我注意到一个新的公司，Company3也使用单个数据点，例如账户6000，它不遵循先前公司的方式，这使得uzi的递归cte不适用。

因此我觉得有必要改变这个问题，但我相信这个复杂问题会发出一个新问题，而不是对我之前的问题进行编辑，因为该解决方案会产生很大的影响。

我需要从Excel工作簿中读取数据，其中数据以这种方式存储：

Company       Accounts
Company1      (#3000...#3999)
Company2      (#4000..#4019)+(#4021..#4024)
Company3      (#5000..#5001)+#6000+(#6005..#6010)

我认为由于某些公司（例如Company3具有我需要的#6000帐户的单一值），在此步骤中，会创建以下外观的结果集：

Company       FirstAcc LastAcc
Company1      3000     3999
Company2      4000     4019
Company2      4021     4024
Company3      5000     5001
Company3      6000     NULL
Company3      6005     6010

然后我将使用此表并使用仅有整数的表来连接它以获得最终表的外观，例如我链接问题中的表。

有没有人有任何想法？

Answer 1

我从另一个问题对@uzi解决方案进行了一些编辑，其中我添加了另外三个CTE并使用了像LEAD()和ROW_NUMBER()这样的窗口函数来解决问题。我不知道是否有更简单的解决方案，但我认为这是有效的。

with cte as (
select 
    company, replace(replace(replace(accounts,'(',''),')',''),'+','')+'#' accounts 
from 
    (values ('company 1','#3000..#3999'),('company 2','(#4000..#4019)+(#4021..#4024)'),('company 3','(#5000..#5001)+#6000+(#6005..#6010)')) data(company, accounts)
)
, rcte as (
    select 
        company, stuff(accounts, ind1, ind2 - ind1, '') acc, substring(accounts, ind1 + 1, ind2 - ind1 - 1) accounts
    from 
        cte
        cross apply (select charindex('#', accounts) ind1) ca
        cross apply (select charindex('#', accounts, ind1 + 1) ind2) cb
    union all
    select
        company, stuff(acc, ind1, ind2 - ind1, ''), substring(acc, ind1 + 1, ind2 - ind1 - 1)
    from
        rcte
        cross apply (select charindex('#', acc) ind1) ca
        cross apply (select charindex('#', acc, ind1 + 1) ind2) cb
    where
        len(acc)>1
) ,cte2 as (

    select company, accounts as  accounts_raw, Replace( accounts,'..','') as accounts,
        LEAD(accounts) OVER(Partition by company ORDER BY accounts) ld,
        ROW_NUMBER() OVER(ORDER BY accounts) rn 
    from rcte
) , cte3 as (

    Select company,accounts,ld ,rn 
    from cte2 
    WHERE ld not like '%..' 
) , cte4 as (
    select * from cte3 where accounts not in (select ld from cte3 t1 where t1.rn < cte3.rn)
)

SELECT company,accounts,ld from cte4
UNION
SELECT DISTINCT company,ld,NULL from cte3 where accounts not in (select accounts from cte4 t1)

option (maxrecursion 0)

<强>结果：

Answer 2

一个好的t-sql分割器功能使这很简单;我建议delimitedSplit8k。这也将比递归CTE表现得更好。首先是样本数据：

-- your sample data
if object_id('tempdb..#yourtable') is not null drop table #yourtable;
create table #yourtable (company varchar(100), accounts varchar(8000));
insert #yourtable values ('Company1','(#3000...#3999)'),
('Company2','(#4000..#4019)+(#4021..#4024)'),('Company3','(#5000..#5001)+#6000+(#6005..#6010)');

和解决方案：

select 
  company, 
  firstAcc = max(case when split2.item not like '%)' then clean.Item end),
  lastAcc  = max(case when split2.item     like '%)' then clean.Item end)
from #yourtable t
cross apply dbo.delimitedSplit8K(accounts, '+') split1
cross apply dbo.delimitedSplit8K(split1.Item, '.') split2
cross apply (values (replace(replace(split2.Item,')',''),'(',''))) clean(item)
where split2.item > ''
group by split1.Item, company;

结果：

company   firstAcc   lastAcc
--------- ---------- --------------
Company1  #3000      #3999
Company2  #4000      #4019
Company2  #4021      #4024
Company3  #6000      NULL
Company3  #5000      #5001
Company3  #6005      #6010

Answer 3

我相信列表（＃6005 ..＃6010）在您的Excel文件中表示为＃6005＃6006＃6007＃6008＃6009＃6010。如果这是真的并且没有间隙，请尝试此查询

with cte as (
select 
    company, replace(replace(replace(accounts,'(',''),')',''),'+','')+'#' accounts
from 
    (values ('company 1','#3000#3001#3002#3003'),('company 2','(#4000#4001)+(#4021#4022)'),('company 3','(#5000#5001)+#6000+(#6005#6006)')) data(company, accounts)
)

, rcte as (
    select 
        company, stuff(accounts, ind1, ind2 - ind1, '') acc, substring(accounts, ind1 + 1, ind2 - ind1 - 1) accounts
    from 
        cte
        cross apply (select charindex('#', accounts) ind1) ca
        cross apply (select charindex('#', accounts, ind1 + 1) ind2) cb
    union all
    select
        company, stuff(acc, ind1, ind2 - ind1, ''), substring(acc, ind1 + 1, ind2 - ind1 - 1)
    from
        rcte
        cross apply (select charindex('#', acc) ind1) ca
        cross apply (select charindex('#', acc, ind1 + 1) ind2) cb
    where
        len(acc)>1
)

select
    company, min(accounts) FirstAcc, case when max(accounts)  =min(accounts) then null else max(accounts) end LastAcc
from (
    select
        company, accounts, accounts - row_number() over (partition by company order by accounts) group_
    from 
        rcte
    ) t
group by company, group_

option (maxrecursion 0)

Answer 4

看起来您标记了SSIS，因此我将使用脚本任务为其提供解决方案。所有其他示例都需要加载到临时表。

使用普通阅读器（可能是Excel）并加载
添加脚本转换组件
编辑组件
输入列 - 检查公司和帐户
输入和输出 - 添加新输出并将其命名为CompFirstLast
向其添加三列 - 公司字符串，First int和Last int

打开脚本并粘贴以下代码

public override void Input0_ProcessInputRow(Input0Buffer Row)
{

//Create an array for each group to create rows out of by splitting on '+'

string[] SplitForRows = Row.Accounts.Split('+'); //Note single quotes denoting char 

//Deal with each group and create the new Output
for (int i = 0; i < SplitForRows.Length; i++) //Loop each split column
    {
        CompFirstLastBuffer.AddRow();
        CompFirstLastBuffer.Company = Row.Company; //This is static for each incoming row

        //Clean up the string getting rid of (). and leaving a delimited list of #
        string accts = SplitForRows[i].Replace("(", String.Empty).Replace(")", String.Empty).Replace(".", String.Empty).Substring(1);

        //Split into Array
        string[] accounts = accts.Split('#');

        // Write out first and last and handle null
        CompFirstLastBuffer.First = int.Parse(accounts[0]);

        if (accounts.Length == 1)
            CompFirstLastBuffer.Last_IsNull = true;
        else
            CompFirstLastBuffer.Last = int.Parse(accounts[1]);

    }
}

确保使用正确的输出。

查找从单个连续值字符串

4 个答案: