我正在使用PHP mysqli数据库。我在数据库中检索一些数据并在in_array条件下使用它。我的PHP代码是:
total database memberno(0001,0002,0003,0004,0005,0006,0007,0008 to 0016)
$relation_ship_no_findempty = '00010001';
$myid = '1';
$select_query_findempty = "select * from member_tree where relation_ship_no LIKE '%{$relation_ship_no_findempty}%' AND tree_id > '$myid' AND x_position = '2'";
$run_findempty = mysqli_query($con,$select_query_findempty);
while ($row_findempty = mysqli_fetch_array($run_findempty)) {
$member_no = $row_findempty[ 'member_no'];
$arr1 = array('0005','0016', '0010', '0013', '0006');
if (!in_array($member_no, $arr1)) {
$member_no."<br>";
}
}
出现的输出:
0001
0002
0003
我的预期输出是:
3
有人可以帮助我吗?
答案 0 :(得分:0)
这将返回行数:
$run_findempty = mysqli_query($con,$select_query_findempty);
$num_rows = mysqli_num_rows($run_findempty);
官方文件:
答案 1 :(得分:0)
$arr1 = array('0005','0016', '0010', '0013', '0006');
你可以在查询中过滤使用implode和count
$select_query_findempty = "select * from member_tree where relation_ship_no LIKE '%{$relation_ship_no_findempty}%' AND tree_id > '$myid' AND x_position = '2' and member_no not in (".implode(',', $arr1).")";
$count = mysqli_num_rows($run_findempty);